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3 years ago

EASY MATH PROBLEM! Please help me! Will mark brainliest for sure!

Mathematics

2 answers:

sp2606 [1]3 years ago

6 0

Answer:

The answer would be A

Step-by-step explanation:

Use the formula for |A| <= B which is: -B <= A <= B

For this example you would do:

1. Insert the numbers into the formula: -6 <= 2x - 8 <= 6

2. first do the math for -6 <= 2x-8 which is 1 <= x

3. then do the math for 2x - 8 <= 6 which is x <= 7

4. Put that together and you get 1 <= x <= 7

Good luck on the other questions!

OverLord2011 [107]3 years ago

3 0

Answer:

Step-by-step explanation:

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irina1246 [14]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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bearhunter [10]

Answer:

Step-by-step explanation:

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3 years ago

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Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?

siniylev [52]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}$

Step-by-step explanation:

$12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}$