Answer: $128
Step-by-step explanation: So first Bob earned 8 dollars. Then he started earning 10 dollars a day every week for 2 weeks. that would have been 148 dollars (plus the 8 dollars he earned in the beginning), but he took a break once a week, subtracting 20 dollars from his pay, giving him 128 dollars in total.
Let me know if this was helpful! :D
Answer:
D. 76
Step-by-step explanation:
because students that has 5 absences and less most likely to get higher than 75 marks. The student who has 8 absences studied at home, he's a genius
(3x86)+(9,538+629) = 10,425
Hope this helps
Answer: Remember that the tens place is two moves to the left of the decimal point (if it exists). To round to the nearest ten (nearest 10), we use the whole numbers place to determine whether the tens place rounds up or stays the same.
Solution steps:
Step 1: Locate and underline the tens place () and look to digit to the right (6):
36
Step 2: In this case, the digit to the right 6 is 5 or above. So, we add 1 to the tens place (). The digit(s) after the (6) are dropped. Thus, we get 40 as answer.
In short: 36 rounded to the nearest tens is 40.
Step-by-step explanation:
The equation form of a circle is (x - a)² + (y - b)² = r²
Equation 1:
x² - 4x + y² + 12y - 20 = 0 ⇒ use the completing the square method for x² - 4x and y² + 12y
x² - 4x = (x - 2)² - 4
y² + 12y = (y + 6)² - 36
Put them back together, we have
(x - 2)² - 4 + (y + 6)² - 36 - 20 = 0
(x - 2)² + (y + 6)² -4 - 36 - 20 = 0
(x - 2)² + (y + 6)² - 60 = 0
(x - 2)² + (y + 6)² = 60
Equation 2:
x² + y² + 6x - 8y - 10 = 0
(x² + 6x) + (y² - 8y) -10 = 0
(x + 3)² - 9 + (y - 4)² -16 - 10 = 0
(x + 3)² + (y - 4)² - 9 - 16 - 10 = 0
(x + 3)² + (y - 4)² - 35 = 0
(x + 3)² + (y - 4)² = 35
Equation 3:
3x² + 12x + 3y² +18y - 15 = 0
3 [x² + 4x + y² + 6y - 5] = 0
x² + 4x + y² + 6y - 5 = 0
(x² + 4x) + (y² + 6y) - 5 = 0
(x + 2)² - 4 + (y + 3)² - 9 - 5 = 0
(x + 2)² + (y + 3)² - 4 - 9 -5 = 0
(x + 2)² + (y + 3)² - 18 = 0
(x + 2)² + (y + 3)² = 18
Equation 4:
5x² + 5y² - 10x + 20y - 30 = 0
5 [x² + y² - 2x + 4y - 6] = 0
x² + y² - 2x + 4y - 6 = 0
(x² - 2x) + (y² + 4y) - 6 = 0
(x - 1)² - 2 + (y + 2)² - 4 - 6 =0
(x - 1)² + (y + 2)² - 2 - 4 - 6 = 0
(x - 1)² + (y + 2)² - 12 = 0
(x - 1)² + (y + 2)² = 12
Equation 5:
2x² + 2y² - 24x - 16y -8 = 0
2 [x² + y² - 12x - 8y - 4] = 0
x² + y² - 12x - 8y - 4 = 0
(x² - 12x) + (y² - 8y) - 4 = 0
(x - 6)² - 36 + (y - 4)² - 16 - 4 = 0
(x - 6)² + (y - 4)² -36 - 16 - 4 = 0
(x - 6)² + (y - 4)² - 56 = 0
(x - 6)² + (y - 4)² = 56
Equation 6:
x² + y² + 2x - 12y - 9 = 0
(x² + 2x) + (y² - 12y) - 9 = 0
(x + 1)² - 1 + (y - 6)² - 36 - 9 = 0
(x + 1)² + (y - 6)² - 1 - 36 - 9 = 0
(x + 1)² + (y - 6)² - 46 = 0
(x + 1)² + (y - 6)² = 46
