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qaws [65]
3 years ago
12

Montana Company sold merchandise with a retail price of $ 29 comma 000 for cash. Montana Company is required to collect 6 ​% sta

te sales tax. The total cash received from customers​ was
Mathematics
1 answer:
cluponka [151]3 years ago
3 0

Answer:

The total cash received is $30740.

Step-by-step explanation:

Montana Company sold merchandise with a retail price of $ 29,000 for cash. Montana Company is required to collect a 6 ​% state sales tax.

Therefore, the total cash received from customer = Retail Price + State Sales Tax.

= 29000 + 29000 \times \frac{6}{100}

= $30740

Hence, the total cash received is $30740. (Answer)

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Answer:

Step-by-step explanation:

To solve equations like this you need to to get x by itself.

So, Let's multiply both sides by 5 to get rid of 5.

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If the shape of an object changes the perimeter will always change true or false
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3 years ago
Suppose that the population mean for income is $50,000, while the population standard deviation is 25,000. If we select a random
Fudgin [204]

Answer:

Probability that the sample will have a mean that is greater than $52,000 is 0.0057.

Step-by-step explanation:

We are given that the population mean for income is $50,000, while the population standard deviation is 25,000.

We select a random sample of 1,000 people.

<em>Let </em>\bar X<em> = sample mean</em>

The z-score probability distribution for sample mean is given by;

               Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = $50,000

            \sigma = population standard deviation = $25,000

            n = sample of people = 1,000

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample will have a mean that is greater than $52,000 is given by = P(\bar X > $52,000)

  P(\bar X > $52,000) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{52,000-50,000}{\frac{25,000}{\sqrt{1,000} } } ) = P(Z > 2.53) = 1 - P(Z \leq 2.53)

                                                                    = 1 - 0.9943 = 0.0057

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.53 in the z table which has an area of 0.9943.</em>

Therefore, probability that the sample will have a mean that is greater than $52,000 is 0.0057.

5 0
3 years ago
A blackjack is a 10-point card and an ace for a value of 21. Use your answers to parts (a), (b), and (c) to determine the probab
kondor19780726 [428]

Answer:

Results:

0.1432

0.0045

0.0905

0.0483

Step-by-step explanation:

Step a:

P(A or 10, A or 10) = 20/52 * 19/51 = 5/13 / 19/51 = 95/663 = 0.1432

Step b:

P(A A) = 4/52 * 3/51 = 1/13 * 1/17 = 1/221 = 0.0045

Step c:

P(10 10) = 16/52 * 15/51 = 4/13 * 5/17 = 20/221 = 0.0905

Step d:

P(A 10 or 10 A) = 2 * 4/52 * 16/51 = 2/13 * 16/51 = 32/663 = 0.0483

As well we get the probability by subtracting a,  b and c:  

P(blackjack): 0.1432 - 0.0905 - 0.0045 = 0.0482  

7 0
4 years ago
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