Answer:
m<T = , m<M = and m<Z =
Step-by-step explanation:
From the given ∆TMZ, let the measure angle T be represented by T.
So that,
m<M = 2T + 6°
m<Z = 5T - 50°
Sum of angles in a triangle =
T + (2T + 6°) + (5T - 50°) =
8T - =
8T = +
=
T =
=
Therefore,
i. m<T =
ii. m<M = 2T + 6°
= 2 x + 6°
=
m<M =
iii. m<Z = 5T - 50°
= 5 x - 50°
= - 50°
=
m<Z =
You know how a puppy is a kind of dog, but not all dogs are puppies? Well, the same thing is true for lots of other categories of things, including squares and rectangles.
Since the problem is to prove that the two triangles are congruent by applying SSS (side -side -side) congruence theorem, the missing or the additional information that can be shown in the solution is the third side of both triangles must be also equal and congruent. Since in SSS theorem, all sides of a given triangle must be congruent to the opposite three sides of the second triangle.
Answer:
(-10,-7)
Step-by-step explanation:
first reflect over x=-3
(-7,-10)
then reflect over y=x
(-10,-7)
It's for sure reflection symmetry, I think it's also point reflection (the point must be in the very middle of the figure). I hope it will help you somehow :)
