Answer:
C) 301.8
Explanation:
Hello!
In this case, since the solution is composed by water and salt, the total resulting mass comes up from adding the mixed mass of each one:
Thus, we plug in to obtain:
Therefore, the answer should be C) 301.8 as it has four significant figures.
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Answer:
Ka = 1.78 × 10⁻⁵
Explanation:
Let's consider the following thermochemical equation.
CH₃COOH(aq) + H₂O(l) → CH₃COO⁻(aq) + H₃O⁺(aq) ∆G° = 27.1 kJ/mol
At 25°C (298 K), we can find the equilibrium constant (Ka) using the following expression.
∆G° = - R × T × lnKa
where,
R: ideal gas constant
T: absolute temperature
27.1 × 10³ J/mol = - (8.314 J/K.mol) × 298 K × lnKa
Ka = 1.78 × 10⁻⁵
Answer:b yes b yes c no c yes d yes d no
Explanation: wanna trade r o b l o x acc
Hey There!
Assuming the part of the round flask containing liquid to be perfect sphere, we can calculate it's volume.
Given diameter of sphere = 24 cm
Therefore radius of the sphere, r= 24/2= 12 cm
Volume of the sphere of diameter 24 cm = (4/3)*pi*r³ = 7,238.23 cm3
Conversion of cm³ to L
1 L= 1 dm³
1 dm = 10 cm
Therefore 1L= 1 dm³ = 1000 cm³
So the volume of liquid in the round flask = 7.24 L( round of to nearest 0.01 L)