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3 years ago

Put the numbers in order from least to greatest. - 29 , -5.39, - 27 5 , -5 7 20

Mathematics

2 answers:

shtirl [24]3 years ago

7 0

The answer to your question is.....

-29,-27,-5.39,-5,5,7,20

Lostsunrise [7]3 years ago

3 0

The order is -57.20, -29,-27.5, -5.39

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Anon25 [30]

Answer:

1). t ≥ - $\frac{3}{2}$

2). k ≥ $\frac{16}{3}$

3). y < - $\frac{1}{2}$

4). b > $\frac{250}{9}$

5). w ≤ 0

Step-by-step explanation:

1). $14(\frac{1}{2}-t)\leq 28$

$\frac{14}{14}(\frac{1}{2}-t)\leq \frac{28}{14}$

$\frac{1}{2}-t\leq 2$

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2). 15k + 11 ≤ 18k - 5

15k - 18k ≤ -5 - 11

-3k ≤ - 16

3k ≥ 16

k ≥ $\frac{16}{3}$

3). 44y > 11 + 88y - 22y

44y > 11 + 66y

44y - 66y > 11

-22y > 11

22y < -11

$\frac{22y}{22}$

y < $-\frac{1}{2}$

4). $\frac{7}{9}(b - 27) > \frac{49}{81}$

$\frac{7}{9}(b - 27)\times \frac{9}{7} > \frac{49}{81}\times \frac{9}{7}$

(b - 27) > $\frac{7}{9}$

b > $\frac{7}{9}+27$

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5). 11w - 8w ≥ 14w

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3 years ago

Simplified (4x3 - 5x2 + 3x) + (-2x3 - x2 + 6x)

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Answer:

Answer is imaginary roots

Step-by-step explanation:

$({4x}^{3} - {5x}^{2} + 3x) + ( - {2x}^{3} - {x}^{2} + 6x) \\ 2 {x}^{3} - 6 {x}^{2} + 9x = 0 \\ dividing \: by \: x \\ 2 {x}^{2} - 6x + 9 = 0 \\ dividin g\: by \: 2 \\ {x}^{2} - 3x + \frac{9}{2} = 0 \\ shifting \: the \: constant \: term \: on \: right \: side \\ {x}^{2} - 3x = - \frac{9}{2} \\ adding \: \frac{1}{2} \times (coefficient \: of \: x) \: whole \: square \\$

On solving the above mentioned equation we get some imaginary values.

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