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Aliun [14]
3 years ago
7

How many different arrangements can be made with the letters from the word space

Mathematics
2 answers:
alekssr [168]3 years ago
4 0
120 different arrangements
Nat2105 [25]3 years ago
4 0
  I can absolutely help you with this! :)

  There are 120 different arrangements used from the word space.

Hope this Helps! :) please mark me Brainiest! :)
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The length of a rectangle is (x+3) inches long,and the width is 3⅖ inches.If the area is 15 3/10 square inches,write an equation
tino4ka555 [31]

Answer:

(x + 3) = 9/2

Step-by-step explanation:

Here, we want to write an equation to find the length of the rectangle

Mathematically;

Area of rectangle = length * breadth

15 3/10 = (x + 3) * 3 2/5

(x + 3) = 15 3/10 divided by 3 2/5

(x + 3) = 153/10 * 5/17

(x + 3) = 9/2

8 0
3 years ago
For spirit week at whoville Middle School students were encouraged to wear the school colors of burgundy and gold of the 1,500 s
eimsori [14]

Answer:

20%

Step-by-step explanation:

8 0
3 years ago
Find the x and y intercepts 5y + 3x = 15
Tomtit [17]
First, find the x-intercept.

The x-intercept will be at the point (x, 0) where x is any real number. If we substitute the x-coordinate and the y-coordinate for the x and y variables in the equation, we can solve for x.

5y + 3x = 15
5(0) + 3x = 15
3x + 15
x = 5

We found the x-intercept now find the y-intercept with the same process.

The y-intercept will be at the point (0, y) where y is any real number.

5y + 3x = 15
5y + 3(0) = 15
5y = 15
y = 3

So, the x-intercept is (5, 0) and the y-intercept is (0, 3)
8 0
3 years ago
Solve the following radical equation.<br>21*+2 - 18-3 = 18+9<br>x =​
stiks02 [169]

Answer:

x = -9, -2, and 3.

just set everything possible to 0.

since 0 = 0 it must be true.

4 0
3 years ago
What is the product? 2x+8 x2 + 3x-4 x(x-4)(x-1) 20x+4) 2 (x+4)(x-4) 2x(x-1) 2x(x+4)​
guajiro [1.7K]

=−640x10+1280x9+19904x8−40728x7−144488x6+323904x5−162304x4+1024x3+2048x2

step by step

(2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x(x+4)

=((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(x+4)

=((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(x)+((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(4)

=−640x10+3840x9+4544x8−58904x7+91128x6−40608x5+128x4+512x3−2560x9+15360x8+18176x7−235616x6+364512x5−162432x4+512x3+2048x2

=−640x10+1280x9+19904x8−40728x7−144488x6+323904x5−162304x4+1024x3+2048x2

7 0
3 years ago
Read 2 more answers
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