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Aliun [14]
3 years ago
7

How many different arrangements can be made with the letters from the word space

Mathematics
2 answers:
alekssr [168]3 years ago
4 0
120 different arrangements
Nat2105 [25]3 years ago
4 0
  I can absolutely help you with this! :)

  There are 120 different arrangements used from the word space.

Hope this Helps! :) please mark me Brainiest! :)
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For problems 29 - 31 the graph of a quadratic function y=ax^2 + bx + c is shown. Tell whether the discriminant of ax^2 + bx + c
Elan Coil [88]

Answer:

29) discriminant  is positive

30) discriminant  is 0

31) discriminant  is negative

Step-by-step explanation:

the graph of a quadratic function y=ax^2 + bx + c is shown. Tell whether the discriminant of ax^2 + bx + c = 0 is positive, negative, or zero.

In the graph of question number 29 we can see that the graph intersects the x axis at two points

so the equation has 2 solutions.

When the equation has two solution then the discriminant is positive

In the graph of question number 30 we can see that the graph intersects the x axis at only one point

so the equation has only  1 solution.

When the equation has only one solution then the discriminant is equal to 0

In the graph of question number 30 we can see that the graph does not intersects the x axis  

so the equation has 2 imaginary solutions.

When the equation has two imaginary solutions then the discriminant is negative

3 0
4 years ago
A hotel house keeper cleaned 1/3 on
Aleksandr-060686 [28]

Answer:

dunno

Step-by-step explanation:

hope this helps has hdhd

3 0
3 years ago
PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The
Nookie1986 [14]
<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}

<h3><u>Step-by-step explanation:</u></h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

  • Radius of smaller circle be r .
  • Radius of smaller circle be r .
  • Area of shaded region be \bf Area_{shaded}

\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2  \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2)  \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2]  \\\\\bf\implies Area_{shaded}  = \pi [ 100cm^2-16cm^2]  \\\\\bf\implies Area_{shaded}  = \pi \times 84cm^2  \\\\\bf\implies Area_{shaded}  = \dfrac{22}{7}\times 84cm^2  \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}

<h3><u>Hence </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> the</u><u> </u><u>shaded </u><u>region</u><u> is</u><u> </u><u>2</u><u>6</u><u>4</u><u> </u><u>cm²</u><u>.</u></h3>

5 0
3 years ago
A coin is tossed twice. Let H represents heads, T represents tails, and the combination of the two letters represent the outcome
denis23 [38]

Answer:

{HH, HT, TH, TT}

Step-by-step explanation:

The set of all possible outcomes in tossing a coin twice is;

{HH, HT, TH, TT}

In the first toss the coin may land Heads. In the second toss the coin may land Heads or Tails. This can be represented as;

HH, HT

Heads in the first and second tosses. Heads in the first toss followed by a Tail in the second toss.

In the first toss the coin is also likely to land Tails. In the second toss the coin may land Heads or Tails. This can be represented as;

TH, TT

Tails in the first toss followed by a Head in the second toss. Tails in the first and second tosses.

Combining these two possibilities will give us the set of all possible outcomes in tossing a coin twice is;

{HH, HT, TH, TT}

4 0
4 years ago
? Explain idk what that means
Korvikt [17]

7 people, 7 walls, 48 minutes

Each person paints 1 wall in 48 minutes

20 persons, 20 walls

Each can paint 1 wall in 48 minutes so it will

take 48 minutes.

5 0
4 years ago
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