9514 1404 393
Answer:
60, 57, 54, 51, ...
Step-by-step explanation:
The general term of an arithmetic sequence is ...
an = a1 +d(n -1)
We would like to find the first term (a1) and the common difference (d). We can use the two given terms to find these parameters.
a10 = 33 = a1 +d(10 -1)
a22 = -3 = a1 +d(22 -1)
Subtracting the first equation from the second, we get ...
(-3) -(33) = (a1 +21d) -(a1 +9d)
-36 = 12d
-3 = d
Using this value in the first equation, we can find a1.
33 = a1 +9(-3) = a1 -27
60 = a1 . . . . . . . . . . . . . . add 27 to both sides
So, our sequence has first term 60 and a common difference of -3.
The first 4 terms are ...
60, 57, 54, 51, ...
Answer:
The probability that a student pick from this group at random either has blue or brown eyes is
P = 40/65 = 0.6154
P = 61.54%
Corrected question;
In a group of 65 students 10 have brown eyes and 30 have blue eyes. Find the Probability that a student pick from this group at random either has blue or brown eyes
Step-by-step explanation:
Given;
Total number of students = 65
Number of students with either blue or brown eyes;
= 10+30 = 40
The probability that a student pick from this group at random either has blue or brown eyes is
P = 40/65 = 0.6154
P = 61.54%
Answer: D
Step-by-step explanation:
I substituted in the value of x (2) to see if it gave me the value of y (1) because that’s the point it gave on g(x).
The only equation that worked was D.
1/2*2=1 then 1^2=1
Answer:
y=3x-10
Step-by-step explanation:
To find equation of the line passing through points
and A(xa, ya) and B(xb, yb)
, we use formula: y-ya = yb-ya/xb-xa (x-xa)
In this example we have xa=
6 ,ya=
8 , xb=5
and yb=5
. So,
y-ya= yb-ya / xb-xa (x-xa)
y-8 = 5-8/ 5-6 (x-6)
y-8= 3(x-6)
y-8= 3x-18
y-8= 3x-10
y = 3x - 10
