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Juli2301 [7.4K]
2 years ago
8

Jill collected honey from 9 different beehives, and recorded the amount collected, in gallons, from each hive in the line plot s

hown:
She wants to write the value of each point marked on the number line above (Points A-D) in gallons. What is the value of A using fractions?
My brother needs help I don't remember this devilish stuff

Mathematics
1 answer:
RideAnS [48]2 years ago
5 0

Answer:

A= 6/8 gallons

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f(x) has domain , and range . A 2-column table with 5 rows. Column 1 is labeled x with entries negative 4, negative 2, 0, 2, 4.
laiz [17]

Answer:

Domain: {-4, -2, 0, 2, 4}

Range: {-2, -1, 0 1, 2}

Step-by-step explanation:

5 0
3 years ago
Can some1 pls explain to me how to do this??! Katrina is building a deck. She cuts 3 lengths of wood from a 72-inch board. The f
uysha [10]
Rewriting the question, the given lengths that were cut from the board were 30 3/4 inches, 12 1/4 inches, and 16 1/4 inches. To obtain the remaining length of the board, all of the measurements cut are to be added and subtracted from 72 inches. This is shown below:

30 3/4 + 12 1/4 + 16 1/4 = 237/4 = 59.25 inches.

Remaining length of board = 72 - 59.25 = 12.75 inches.

Therefore, there will be 12.75 inches remaining of the board.
6 0
3 years ago
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
2 years ago
The regular price of a tablet case is $38.45. During a sale, the case was marked as 25% off. What was the approximate price of t
Pani-rosa [81]
C 28.84 just multiply 38.45 by .25 then you should get 9.6125 you subtract 38.45 by 9.6125 and get 28.84
6 0
3 years ago
Read 2 more answers
Find the approximate distance between (-5, 8) and (10, -7). Round your answer to two decimal places.
nadya68 [22]
Distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(-5,8)(10,-7)

d = sqrt (10 - (-5)^2 + (-7 - 8)^2
d = sqrt (10 + 5)^2 + (- 15^2)
d = sqrt (15^2) + (-15^2)
d = sqrt 225 + 225
d = sqrt 450
d = 21.21
5 0
3 years ago
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