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8090 [49]
3 years ago
15

The distance between (-2, -5), (3, 5) what is it please help

Mathematics
1 answer:
Bogdan [553]3 years ago
4 0
The difference between the x-values is 5. 
The difference between the y-values is 10. 
Make a triangle with these points. 
The distance is the hypotenuse. 
Use the pythagorean theorem to get the distance. 
Square 5 and 10 to get 25 and 100. 
Add them together to get 125. 
Find the square root of 125. 
It is approximately 11.2 units. 
Hope this helps!
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Answer:

0 tests

Yes, this procedure is better on the average than testing everyone, it makes it less cumbersome.

Step-by-step explanation:

Given the information:

Let P be the probability that a randomly selected individual has the disease = 0.1. N individuals are randomly selected, thereafter, blood samples of each person would be tested after combining all specimens. Should in case one person has the disease then it yields a positive result and test should be set for each person.

Let Y be number tests

For n = 3 there are two possibilities. If no one has the disease then the value is 1 otherwise the value is 4, here P = 0.1

Therefore, for Y = 1

P(Y-1) = P(no one has disease)

= 0.9³

= 0.729

If Y = 4

P(Y-4) = 1-P(y = 1)

= 1 - 0.729 = 0.271

The expected number of tests using this formular gives

E(Y) = 1×0.729 + 4×0.271

E(Y) = 0

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4 years ago
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Step-by-step explanation:

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3 years ago
Pick the decimal equivalent to 3 9/100
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If you have pick it, then you should be offered choices and you should include them in the question.

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Which polynomial function has a leading coefficient of 2, root 4 with multiplicity 3, and root 10 with multiplicity 1?
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Answer:

Step-by-step explanation:

Yes

8 0
3 years ago
Let U={1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, A={1, 2, 3, 4, 5}, B={1, 3, 5, 7} Find A' ∩ B
sineoko [7]

Here given that:

  • U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
  • A = {1, 2, 3, 4, 5}
  • B = {1, 3, 5, 7}

Here let's first find the set A' , by using formula:

→ A' = U - A

→ A' = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} - {1, 2, 3, 4, 5}

→ A' = {6, 7, 8, 9, 10}

Now A' ∩ B is the set of all common elements of A' and B as

→ A' ∩ B = {6, 7, 8, 9, 10} ∩ {1, 3, 5, 7}

→ A' ∩ B = {7}

<em>Hence, </em>A' ∩ B <em> is a singleton set</em>

4 0
3 years ago
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