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erma4kov [3.2K]
3 years ago
8

Can someone help me please?

Mathematics
1 answer:
katrin2010 [14]3 years ago
4 0

Answer:

120,000-30,000=$90000 in bonds or $4500 profit.

Step-by-step explanation:

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son4ous [18]
The perimeter would be 48 feet
6 0
3 years ago
A matched-pairs t-test is NOT an appropriate way to analyze data consisting of which of the following? Measurements of annual in
o-na [289]

Answer:

Step-by-step explanation:

A matched pair t test is one in which the set of data is divided into two sets of data and the test is done to test the difference between the pairs. Sometimes this is called paired t test.\

This is done normally where one group of sample or population can be paired with other group of sample /population.

Hence

A .Measurements of annual income for each twin for 100 randomly selected pairs of twins -- True

B. Measurements of annual income for both individuals in pairs formed by matching 100 people from State A and 100 people from State B based on level of education -- True

C. Measurements of annual income for both individuals in pairs formed by assigning 100 people to pairs at random -- True

D. Measurements of annual income recorded for both spouses of 100 randomly selected married couples  --False here we cannot say paired as these people are not grouped under the same conditions.

7 0
3 years ago
An online file storage site offers a payment plan where users
lozanna [386]

Answer:   95.40

Step-by-step explanation:

7.95*12=95.40

6 0
3 years ago
$72 with a 40% markup
alex41 [277]

Answer:

$100.80

Step-by-step explanation:

40%/100%×72=$28.80

$72+$28.80=$100.80

8 0
3 years ago
1000 households were surveyed. 275 households own a desktop computer, 455 households own a DVD player, 405 households own two ca
icang [17]

Answer:

Step-by-step explanation:

From the given information,

Suppose

X represents the Desktop computer

Y represents the DVD Player

Z represents the Two Cars

Given that:

n(X)=275

n(Y)=455

n(Z)=405

n(XUY)=145

n(YUZ)=195

n(XUZ)=110

n((XUYUZ))=265

n(X ∩ Y ∩ Z) = 1000-265

n(X ∩ Y ∩ Z) = 735

n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)

145 = 275+455 - n(X ∩ Y)

n(X ∩ Y) = 585

n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)

195 = 455+405-n(Y ∩ Z)

n(Y ∩ Z) = 665

n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)

110 = 275+405-n(X ∩ Z)

n(X ∩ Z) = 570

a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)

n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735

n(X ∪ Y ∪ Z) = 50

c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)

n(X ∪ Y ∪ C') = 145-50

n(X ∪ Y ∪ C') = 95

6 0
3 years ago
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