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2 years ago

Ignore circled one and work it out please

Mathematics

1 answer:

mash [69]2 years ago

3 0

Answer:

a. $\frac{(x-7)}{x^2+x-30}$

Step-by-step explanation:

$\huge \frac{x^2-3x-28}{(x^2+10x+24)(x-5)} \\\\\huge {=\frac{x^2-7x+4x-28}{(x^2+6x+4x+24)(x-5)}}\\\\\huge {=\frac{x(x-7)+4(x-7)}{\{x(x+6)+4(x+6)\}(x-5)}}\\\\\huge {=\frac{(x-7)(x+4)}{(x+6)(x+4)(x-5)}}\\\\\huge {=\frac{(x-7)}{(x+6)(x-5)}}\\\\\huge {=\frac{(x-7)}{x^2+(6-5)x+6(-5)}}\\\\\huge {=\frac{(x-7)}{x^2+x-30}}$

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The product of a number and ten is twelve more than the product of the number and five-eighths.

ra1l [238]

Let the unknown number be x.

Given,

$10 * x = 12 + \frac{5}{8} * x$

$10x = 12 + \frac{5x}{8}$

$10x - \frac{5x}{8} = 12$

$\frac{(10x*8)-5x}{8} = 12$

$80x-5x =12*8$

$75x = 96$

x = $\frac{96}{75}$ = 1.28

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3 0

3 years ago

The blue line is the graph of y=-4x + 5. Use the

WARRIOR [948]

Answer:

(1,1)

Step-by-step explanation:

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7 0

2 years ago

Read 2 more answers

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adell [148]

The answer would have to be

7 0

3 years ago

Compare and contrast perpendicular bisected and altitude

elena55 [62]

A perpendicular bisector forms two right angles and splits the line in two equal parts.

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6 0

3 years ago

Which represents the reflection of f(x)=sqrt x over the y axis

zloy xaker [14]

reflection of $f(x)=\sqrt{x}$ over the y axis we get $g(x)=\sqrt{-x}$

Step-by-step explanation:

We need to find the reflection of f(x)=sqrt x over the y axis

So, reflection over y- axis

If the function f(x) is transformed over y-axis then the new function g(x) will be $g(x)= f(-x)$

So, finding reflection of $f(x)=\sqrt{x}$ over the y axis we get:

$g(x)=\sqrt{-x}$

So, reflection of $f(x)=\sqrt{x}$ over the y axis we get $g(x)=\sqrt{-x}$

Keywords: Transformations

Learn more about Transformations at:

#learnwithBrainly

6 0

3 years ago

Ignore circled one and work it out please​

Ignore circled one and work it out please