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2 years ago

The pier is 200 meters long each board is 80 centimeters wide how many boards are in the pier

Mathematics

2 answers:

eduard2 years ago

5 0

1 metre = 100cm
2 metres = 200cm

200 / 80 = 2.5

2 boards is the answer. Please make this answer the brainiest.

Verizon [17]2 years ago

3 0

200 meters = 20000 centimeters
now if each board is 80 centimeters then 20000/80 = 250

250 boards is the correct answer

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2/10 in whole number

Margaret [11]

$\frac{2}{10}$

you just divide 2 by 10, which is

.2

6 0

3 years ago

Evaluate the following expression: 62 − 7(8 + 6 − 32)

Alex Ar [27]

Answer:

188

Step-by-step explanation:

Step 1: Distribute

62 − 7(8 + 6 − 32)

62 + (-7 * 8) + (-7 * 6) + (-7 * -32)

62 + (-56) + (-42) + (224)

Step 2: Combine the first two numbers

(62 - 56) - 42 + 224

6 - 42 + 224

Step 3: Combine the next two number

(6 - 42) + 224

-36 + 224

Step 4: Combine the last two number

-36 + 224

188

Answer: 188

3 0

3 years ago

You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o

anyanavicka [17]

Answer:

$x =\dfrac{45 \sqrt{6}}{ 2}$

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

$\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}$

In order to estimate the point along the shore, x meters from B, the runner should stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

= $\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0$

$-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0$

$\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}$

squaring both sides; we get

$\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}$

$\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}$

By cross multiplying; we get

$49x^2 = 25(54^2+x^2)$

$49x^2 = 25 \times 54^2+ 25x^2$

$49x^2-25x^2 = 25 \times 54^2$

$24x^2 = 25 \times 54^2$

$x^2 = \dfrac{25 \times 54^2}{24}$

$x =\sqrt{ \dfrac{25 \times 54^2}{24}}$

$x =\dfrac{5 \times 54}{\sqrt{24}}$

$x =\dfrac{270}{\sqrt{4 \times 6}}$

$x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}$

$x =\dfrac{45 \sqrt{6}}{ 2}$

8 0

3 years ago

Please help with this

snow_lady [41]

Answer:

B. $- \frac{9}{8}$

Step-by-step explanation:

$\huge\frac{ - 2 {a}^{ - 3} {b}^{2} }{a} \\ \\ \huge = \frac{ - 2 {b}^{2} }{a \times{a}^{ 3} } \\ \\ \huge = \frac{ - 2 {b}^{2} }{{a}^{ 4} } \\ \\ \huge = \frac{ - 2 \times {3}^{2} }{ {( - 2)}^{4} } \\ \\ \huge= \frac{ - 2 \times 9}{16} \\ \\ \huge \red{= - \frac{9}{8} }$

8 0

2 years ago

What is the inverse of the function g(x)= -3(x + 6)? g-1(x) =

Elanso [62]

Here’s the answer. See pictures.

3 0

2 years ago