Rihanna colored ones Brianna color 1/6 of her picture and somebody colored 1/4 of his picture who played more

The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion

Vanyuwa [196]

Answer:

Find the slope of the line that passes through the points shown in the table.

The slope of the line that passes through the points in the table is

.

Step-by-step explanation:

8 0

3 years ago

A measurement template with a historcal value of 25.500 is measured 27 times and a mean value of 25.301 is recorded. What is the

QveST [7]

Complete Question

A measurement template with a historical value of 25.500 mm is measured 27 times and a mean value of 25.301 mm is recorded. What is the percent bias when the tolerance is +/- 0.3?

Answer:

The percent bias is $B = 33.167 \%$

Step-by-step explanation:

From the question we are told that

The historical value is $S = 25.00 \ mm$

The number of times it is measured is n = 7

The mean value is $\= x = \frac{\sum x_i }{n} = 25.301 \ mm$

The tolerance is $t =\pm 0.3 = 0.3 - (-0.3) = 0.6$

Generally the percent bias is mathematically represented as

$B = 100 * \frac{\= x - \tau }{ t}$

=> $B = 100 * \frac{25.301 - 25.5000 }{0.6}$

=> $B = 33.167 \%$

3 0

3 years ago

g A program executes a mix of different instruction types. 25% of the instructions require two clock cycles to execute, 20% requ

Tomtit [17]

Answer:

1.8 cycles

Step-by-step explanation:

The average number of clock cycles per instruction is given by the sum of the product of each possible number of cycles by its likelihood.

1 cycle: 50%

2 cycles : 25%

3 cycles : 20%

4 cycles : 5%

$Avg = 0.5*1+0.25*2+0.20*3+0.05*4\\Avg= 1.8\ cycles$

The average number of clock cycles per instruction is 1.8.

8 0

3 years ago

A golf tournament has five rounds. The players are given scores for each round based on how many strokes they are above or below

Sedaia [141]

Answer:

(A) ∫₁⁵[Xₙ + k] where n ranges from 1 to 5

(B) 73.6

Step-by-step explanation:

The question is clear enough. Kudos!

So there are many players but we're focusing on Ricky.

Ricky has already recorded his score for each of the 5 rounds in the tournament.

The number of strokes in Ricky's record are to be added to or subtracted from a given number 72

ROUND 1: [72 - 5] strokes = 67

ROUND 2: [72 + 6] strokes = 78

ROUND 3: [72 - 2] strokes = 70

ROUND 4: [72 + 4] strokes = 76

ROUND 5: [72 + 5] strokes = 77

(A) Write an expression to represent Ricky's total number of strokes for the five rounds.

Do not panic at this first exercise. You are to write an expression which when evaluated, will give the total number of strokes for all five rounds!

You are already given an abstract number '72' to work with in this question.

It is a fixed quantity which influences the value of strokes for each round.

We will represent this by an algebra, if we have to create the above required expression.

The expression will then be:

∫₁⁵[Xₙ + k] where n ranges from 1 to 5

You already know that the sigma sign '∫' represents summation and that's summation from the subscript '1' to the superscript '5'.

X₁ would be -5, X₂ would be +6, X₃ would be -2, X₄ would be +4, X₅ would be +5

K is the constant 72

(B) What was Ricky's average number of strokes per round?

Out of the 5 rounds, the average number of strokes per round would be

[67 + 78 + 70 + 76 +77] ÷ 5

= 368/5 = 73.6

6 0

3 years ago

If

likoan [24]

It's easy to show that $7\tan(4x)$ is strictly increasing on $x\in\left[0,\frac\pi8\right]$ . This means

$M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3$

and

$m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7$

Then the integral is bounded by

$\displaystyle 7\left(\frac\pi{12} - \frac\pi{16}\right) \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le 7\sqrt3 \left(\frac\pi{12} - \frac\pi{16}\right)$

$\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}$

7 0

2 years ago