The vertical asymptote of the function that are illustrated in the calculus and the function y = 3cot(1/2x) - 4 will be:
B. x = 0
C. x = +-2π
<h3>How to illustrate the information?</h3>
It should be noted that the function that's given from the information illustrated is given as:
y = 3 for (x/2) - 4
It should be noted that there is no phase shift and the period is 2π.
It should be noted that the vertical asymptote will be x = 3πn where no is represented as the integer at n = 0, 1, and -1.
Therefore, the vertical asymptote of the function that are illustrated in the calculus and the function y = 3cot(1/2x) - 4 will be x = 0 and x = +2π.
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Answer
it starts in high school but is not recommended for 9th graders.
Step-by-step explanation:
Let
x----> the length side of the hypotenuse
y----> the length side of the <span>unknown leg
we know that
x=2*y----> equation 1
applying the Pythagoras Theorem
x</span>²=y²+3²-----> equation 2
substitute equation 1 in equation 2
[2*y]²=y²+3²----> 4*y²-y²=9-----> 3*y²=9----> y²=3
y=√3 ft
x=2*y----> x=2*√3 ft
the answer is
<span>the lengths of the three sides are
</span>hypotenuse=2√3 ft
one leg=√3 ft
other leg=3 ft
