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pav-90 [236]
3 years ago
10

Find the value of 26/45 times 5/53 times 28/13 please show fingures and work

Mathematics
1 answer:
hjlf3 years ago
3 0

\bf \cfrac{\stackrel{2}{~~\begin{matrix} 26 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{\underset{9}{~~\begin{matrix} 45 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{53}\cdot \cfrac{28}{~~\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies \cfrac{2\cdot 28}{9\cdot 53}\implies \cfrac{56}{477}

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Step-by-step explanation:

P(0.40/0.30)=1.3

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Answer:

4c+6a\leq120\\\\4c+4a\leq100

Step-by-step explanation:

Let c represents child bikes and a represents adult bikes.

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With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week.

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4c+6a\leq120----(1)\\\\4c+4a\leq100-----(2)

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Hence, the system of inequality best explains whether the company can build 10 child bikes and 12 adult bikes in the week.

4c+6a\leq120\\\\4c+4a\leq100

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