Ask question

Ask question

All categories

3 years ago

7

If an object that is 85 ft. long is represented on a scale drawing as a line 5 in. long, what is the scale used to make the draw

ing?
A. 1 in. to 17 ft.
B. 5 in. to 85 ft.
C. 2 in. to 35 ft.
D. 3 in. to 51 ft.

1 answer:

wolverine [178]3 years ago

7 0

The answer is A.
85/5 is 17 and scales are unit rates. Also, process of elimination.

You might be interested in

The shape on the left is translated to the shape on the right.

Studentka2010 [4]

Answer:

The answer is C.

3 0

4 years ago

How many shapes did you put together to make 3/2

ella [17]

You put 3 shapes together I believe

5 0

3 years ago

Solve for x.<br> 4(2x - 1) - 7 = 4 - x + 6

Akimi4 [234]

<span>The answer is that x = 21/9.

Start with the original: 4(2x - 1) - 7 = 4 - x + 6
Now distribute the 4:</span> <span> 8x - 4 - 7 = 4 - x + 6.
Now combine the like terms. 8x - 11 = -x + 10.
Now add x to both sides. 9x - 11 = 10.
Now add 11 to both sides. 9x = 21.
And divide by 9 on both side. x = 21/9. </span>

6 0

3 years ago

Read 2 more answers

Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

<u>Algebra I</u>

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em /> $\displaystyle L = \sqrt{4kt - p}$

<u>Step 2: Solve for </u><u><em>k</em></u>
We can use equality properties to help us rewrite the equation to get <em>k</em> as our subject:

Let's first <em>square both sides</em>:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, <em>add p to both sides</em>:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, <em>divide 4t by both sides</em>:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$

We can rewrite the new equation by swapping sides to obtain our final expression:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}$

∴ we have <em>changed</em> the subject of the formula.

---

Learn more about Algebra I: brainly.com/question/27698547

---

Topic: Algebra I

6 0

2 years ago

Please helppppp<br><br> A. Yes;19<br><br> B. No

Vadim26 [7]

Answer:

Yes

Step-by-step explanation:

7 0

3 years ago