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ozzi
3 years ago
7

If an object that is 85 ft. long is represented on a scale drawing as a line 5 in. long, what is the scale used to make the draw

ing?
A. 1 in. to 17 ft.
B. 5 in. to 85 ft.
C. 2 in. to 35 ft.
D. 3 in. to 51 ft.
Mathematics
1 answer:
wolverine [178]3 years ago
7 0
The answer is A.
85/5 is 17 and scales are unit rates. Also, process of elimination.
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Is 3/5 greater then 3/6
Tcecarenko [31]
Yes, for 3/5= 18/30 and 3/6= 15/30
4 0
3 years ago
In J, K is the midpoint. The coordinates of ) are (2, 2), and the coordinates of Kare (10, 11). What are the coordinates of L?
DiKsa [7]

Answer:

L(18, 20)

Step-by-step explanation:

In JL, K is the midpoint. The coordinates of J are (2, 2), and the

coordinates of K are (10, 11). What are the coordinates of L?

Solution:

If O(x, y) is the midpoint between two points A(x_1,y_1) and B(x_2,y_2). The equation to determine the location of O is given by:

x=\frac{x_1+x_2}{2} \\\\y=\frac{y_1+y_2}{2}

Since JL is a line segment and K is the midpoint. Given the location of J as (2, 2) and K as (10, 11). Let (x_2,y_2) be the coordinate of L. Therefore:

10=\frac{2+x_2}{2} \\\\20=2+x_2\\\\x_2=18

11=\frac{2+y_2}{2} \\\\22=2+y_2\\\\y_2=20

Therefore L = (18, 20)

4 0
3 years ago
Find the unknown length plz
tigry1 [53]
I
tan(32)x21=13mm
j
7.32/cos(66)=17.9cm
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tan(34)x26.8=18m
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:)Good luck in Math

7 0
3 years ago
The point (−3, 1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of
Ivenika [448]

The length of the hypotenuse = √(-3^2 +1^2) = √10

The point -3,1 tell us the length of y is 1 and the length of x is 3.

This would make opposite = 1 and adjacent = -3

Sinθ = opposite/hypotenuse =  1/√10  = √10/10

Cosθ = adjacent/hypotenuse = -3/√10  = - 3√10/10

Tanθ = opposite/adjacent = 1/-3 = -1/3

6 0
3 years ago
Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 5% of all
Gnom [1K]

Answer:

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

Step-by-step explanation:

For each visitor of the website, there are only two possible outcomes. Either they are looking for the website, or they are not. The probability of a customer being looking for the website is independent of other customers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of all visitors to the website are looking for other websites.

So 100 - 5 = 95% are looking for the website, which means that p = 0.95

Find the probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

This is P(X = 2) when n = 4. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = x) = C_{4,2}.(0.95)^{2}.(0.05)^{2} = 0.0135

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

5 0
3 years ago
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