Solve 2x+3y-z=-4 3x+2y+2z=14 x -3z=-13

Mathematics

1 answer:

Zina [86]3 years ago

5 0

Answer:

1. x = -3/2 y+ 1/2z - 2

2. x = -2/3y + -2/3z + 14/3

3. x = 3z - 13

Step-by-step explanation:

solve for x

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Here are four digits.

Bogdan [553]

Answer:

A: 357

(1) 9641

Step-by-step explanation:

With A you really just want to go from the smallest number up so it would be the smallest number possible.

<em>EX.</em> 357 vs. 736 357 is smaller

With 1 you have to go from the highest number to lowest number to get the biggest answer possible.

<em>Ex.</em> 9641 vs. 1946 9641 is larger.

3 0

3 years ago

The sum of three numbers is 18. If every number is a prime number, what are the three numbers?

sleet_krkn [62]

The three numbers are 2, 5, and 11.

The sum of 3 numbers is 18. 2 + 5 + 11 = 18

Since the problem states that every number is a prime number, then the number must be a natural number greater than 1 that has no positive divisors other than 1 and itself.

2 / 1 = 2 OR 2 / 2 = 1 These numbers are prime numbers because their divisors
5 / 1 = 5 OR 5 / 5 = 1 are 1 and itself.
11/1 = 11 OR 11/11 = 1

4 0

3 years ago

Read 2 more answers

Will someone help with this ! I was allowed a retry for it and I don’t know how to do it

pashok25 [27]

Answer:

$\frac{dN}{dt}=k(725-N)\\separating the variables and integrating\\\int \frac{dN}{725-N}=\int kdt+c\\-log (725-N)=kt+c\\log (725-N)=-kt-c\\(725-N)=e^{-kt-c} =e^{-kt} *e^{-c} =Ce^{-kt} \\when t=0,N=400\\725-400=Ce^{0} =C\\C=325\\when t=3,N=650\\725-650=325e^{-3k} \\\frac{75}{325}=(e^{-k})^3\\\\e^{-k} =(\frac{3}{13}) ^{\frac{1}{3} } \\when t=5\\725-N=325(\frac{3}{13}) ^{\frac{5}{3} } =325*\frac{3}{13}*(\frac{3}{13} )^{\frac{2}{3}}\\N=725-75*(\frac{3}{13} )^{\frac{2}{3} }=725-28=697$