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Doss [256]
3 years ago
12

If cos(θ)=2853 with θin Q IV, what is sin(θ)?

Mathematics
1 answer:
marysya [2.9K]3 years ago
7 0

Answer: \sin \theta=\frac{-45}{53}

Step-by-step explanation:

Since we have given that

\cos\theta=\frac{28}{53}

And we know that θ is in the Fourth Quadrant.

So, Except cosθ and sec θ, all trigonometric ratios will be negative.

As we know the "Trigonometric Identity":

\cos^2\theta+\sin^2\theta=1\\\\\sin \theta=\sqrt{1-\cos^2\theta}\\\\\sin \theta=\sqrt{1-(\frac{28}{53})^2}=\sqrt{\frac{53^2-28^2}{53^2}}\\\\\sin \theta=\sqrt{\frac{2025}{53^2}}\\\\\sin \theta=\frac{45}{53}

It must be negative due to its presence in Fourth quadrant.

Hence, \sin \theta=\frac{-45}{53}

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Which polynomial is in standard form?
Romashka-Z-Leto [24]

Answer:

C

Step-by-step explanation:

Standard form is [ ax² + bx + c ]

The exponents and variables determine what comes first.  In [ 11x³ - 6x² + 5x ], we can see that the exponents are going from greatest to least and the last number doesn't have an exponent so it goes last. Essentially we can think of this as sorting each part from greatest to least using exponents -> variables -> number to determine that.

Best of Luck!

7 0
3 years ago
The domain of both
Margarita [4]

Answer:

The domain of function h(x) is set of all real numbers.

Domain: (-∞,∞)

Step-by-step explanation:

Given:

f(x)=x-6

g(x)=x+6

the domain of both the above functions is all real number.

To find domain of :

h(x)=f(x)g(x)

Substituting functions f(x) and g(x) to find h(x)

h(x)=(x-6)(x+6)

The product can be written as difference of squares. [a^2-b^2=(a+b)(a-b)]

∴ h(x)=x^2-36

The degree of the function h(x) is 2 as the exponent of leading term x^2 is 2. Thus its a quadratic equation.

For any quadratic equation the domain is set of all real numbers.  

So Domain of h(x) is (-∞,∞)

7 0
3 years ago
Janice is roller skating at a constant speed away from her house. The first half of the street is flat, but the second half has
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Answer:

It's Z.

Step-by-step explanation:

Because the road is straight at first, then it gets steep.

which means that the road goes down,

kinda like a drop off.

8 0
3 years ago
Read 2 more answers
The bar diagram represents 24 hours in one day and shows a mark at 30%. If you sleep 30% of the day, how many hours do you sleep
Sedbober [7]
30% = 3/10

Number of hours you sleep = 24hours × 3/10
= 24hours ÷ 10 × 3
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Hope this helps! :)
4 0
3 years ago
Write functions for each of the following transformations using function notation. Choose a different letter to represent each f
joja [24]

Answer:

1. Translation: g(x) = f(x-a)+b.

2. Reflection around y-axis: h(x) = f(-x)

3. Reflection around x-axis: k(x) = -f(x)

4. Rotation of 90° : R_{90} (x,y)=(-y,x)

5. Rotation of 180° : R_{180} (x,y)=(-x,-y).

6. Rotation of 270° : R_{180} (x,y)=(y,-x).

Step-by-step explanation:

Let us assume that the transformations namely translation, reflection are applied to a function f(x) and the rotation is applied to the point ( x,y ).

So, according to the options:

We know that 'translation moves the image in horizontal and vertical direction'.

1. As we have to translate the function f(x) 'a' units to the right and 'b' units up. So, the new form of the function becomes g(x) = f(x-a)+b.

Further, we know that 'reflection means to flip the image around a line'.

2. As, we have to reflect the function f(x) around y-axis. The new form of the function is h(x) = f(-x).

3. As, we have to reflect the function f(x) around x-axis. The new form of the function is k(x) = -f(x).

Since, 'rotation turns the image around a point to a certain degree'.

4. As, we have to rotate ( x,y ) counter-clockwise to 90° about the origin, the new form of the function is R_{90} (x,y)=(-y,x).

5. As, we have to rotate ( x,y ) counter-clockwise to 180° about the origin, the new form of the function is R_{180} (x,y)=(-x,-y).

6. As, we have to rotate ( x,y ) counter-clockwise to 270° about the origin, the new form of the function is R_{180} (x,y)=(y,-x).

5 0
3 years ago
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