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White raven [17]
3 years ago
13

Which of the following equations illustrates exponential growth?

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
8 0
X+y=10 is not answering
Reika [66]3 years ago
8 0
B) Y=2^x

It’s the only one using an exponent

Y=2^1 = 2
Y= 2^2 = 4
Y = 2^3 = 8
Y = 2^4 = 16 ...

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Susan solved 200-91 and decided to add her answer to 91 to check her work explain why this strategy works
zhuklara [117]
This strategy works because if you subtract one number from another the sum of the two numbers should be the that is being subtracted from. (In this case, it's 200)
3 0
3 years ago
Read 2 more answers
Simplify sin(3pi minus x)
Slav-nsk [51]

Answer:

sinx

Step-by-step explanation:

hello :

note :

for all x in ℝ :   1) sin(x+2π) = sinx        2)  sin(π-x) = sinx

in this exercice :

3π - x = 2π+(π - x)

sin(3π - x) = sin(2π +(π - x)) =sin(π-x) = sinx

8 0
3 years ago
Find the surface area of the rectangular prism
frutty [35]

Answer:82

Step-by-step explanation:

surface area=pxh + 2xb

p=perimeter of base

h=height

b=area of base

Perimeter of base=7+7+2+2=18

height=3

base area=7x2=14

surface area=18x3+2x14

Surface area=82

7 0
3 years ago
You have a jar of marbles. There are 15 red, 20 blue, 7 green, and 18 yellow marbles. You choose a marble at random from the jar
Nookie1986 [14]

Answer:

the right answer is b. 2/3

6 0
3 years ago
Stephen uses \dfrac{2}{25}
zepelin [54]

Answer:

13\dfrac{3}{4}$ servings

Step-by-step explanation:

Stephen uses \dfrac{2}{25} kilograms of tofu in each serving of his dish.

He has 1\dfrac{1}{10} kilograms of tofu.

We want to determine how many servings Stephen can make.

To do this, we divide the total weight of tofu by the weight per serving.

\dfrac{\text{Total Weight(in kg)}}{\text{Weight(kg) per serving}} =\dfrac{1\dfrac{1}{10}}{ \dfrac{2}{25}}\\ = \dfrac{11}{10}\div  \dfrac{2}{25}\\\\= \dfrac{11}{10}X  \dfrac{25}{2}\\\\= \dfrac{11X25}{10X2}\\\\= \dfrac{275}{20}\\\\=13\dfrac{3}{4}$ servings

Stephen can make 13\dfrac{3}{4}$ servings .

6 0
3 years ago
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