9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.
where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
Answer:
227.08in^2
You want to find the surface area for this problem. SA=2lw+2lh+2hw
Step-by-step explanation:
L=2.5
W=7.4
H=9.6
SA=2lw+2lh+2hw
SA=2(2.5x7.4)+2(2.5x9.6)+2(9.6x7.4)
SA=37+142.08+48
SA=227.08in^2
They are (0,6) because if the center of dilation is point A which means it does not change, while both other points increase their distance from point A by a factor of two (double)
Answer:
The length of the equal side is 27 meters each and that of the unequal side is 36 meters
Step-by-step explanation:
An isosceles triangle is a triangle with two sides being equal (also two equal base angles).
Let us assume the length of the two equal sides to be x meters each, and the length of the unequal side to be y meter. Since the perimeter of the triangle is 90 m, it can be expressed as:
x + x + y = 90
2x + y = 90
But the length of the equal side is three fourth of the unequal side, i.e x = 3/4y
Therefore:
2(3/4y) + y = 90
3/2y + y = 90
2.5y = 90
y = 90/2.5
y = 36 meters
Also x = 3/4 * 36 = 27 meters
The length of the equal side is 27 meters each and that of the unequal side is 36 meters
Answer:
Step-by-step explanation:
The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by
We first compute the n-th derivative of 
, note that
Now, if we compute the n-th derivative at 0 we get
and so the Maclaurin series for f(x)=ln(1+2x) is given by
