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IgorLugansk [536]
3 years ago
14

Determine the rationalized expression of sqrt 9 / sqrt 3 + sqrt x

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:


Step-by-step explanation:


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I believe your first answer would be 3, and your second would be 1/8, but I'm not sure. I hope this helps!

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Convert the angle 0=23/20 radians to degrees,
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207°

Step-by-step explanation:

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What is the slope and are they linear/perpendicular?<br> PHOTO ABOVE
Mandarinka [93]

Answer:

Slope of line 1 = 3

Slope of line 2 = 3

Slope of line 3 = -1/3

Line 1 and 2 are parallel

Line 1 and 3 are perpendicular

Line 2 and 3 are perpendicular

Step-by-step explanation:

Find the slope of each line by using this equation:

y_{2} - y_{1} / x_{2} - x_{1}

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Hope this helps!

8 0
4 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 430 gram setting. It is
Leto [7]

Answer:

t=\frac{435-430}{\frac{29}{\sqrt{23}}}=0.827    

The degrees of freedom are given by:

df=n-1=23-1=22  

And the p value taking in count that we have a bilateral test we got:

p_v =2*P(t_{(22)}>0.827)=0.417  

Since the p value is higher than the significance level of 0.05 we have enough evidence to conclude that the true mean is not significantly different from 430 the required value

Step-by-step explanation:

Information given

\bar X=435 represent the mean for the weight

s=\sqrt{841}=29 represent the sample standard deviation

n=23 sample size  

\mu_o =430 represent the value that we want to verify

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value

System of hypothesis

We are trying to proof if the filling machine works correctly at the 430 gram setting, so then the system of hypothesis for this case are:

Null hypothesis:\mu = 430  

Alternative hypothesis:\mu \neq 430  

In order to cehck the hypothesis the statistic for a one sample mean test is given by

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we have this:

t=\frac{435-430}{\frac{29}{\sqrt{23}}}=0.827    

The degrees of freedom are given by:

df=n-1=23-1=22  

And the p value taking in count that we have a bilateral test we got:

p_v =2*P(t_{(22)}>0.827)=0.417  

Since the p value is higher than the significance level of 0.05 we have enough evidence to conclude that the true mean is not significantly different from 430 the required value

8 0
3 years ago
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