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Fed [463]
2 years ago
15

There are 5 eggs if one egg is taken how much are there

Mathematics
1 answer:
BigorU [14]2 years ago
4 0

Answer:

4 eggs

Step-by-step explanation:

5-1=4

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Four swimmers, Daniela, Camille, Brennan, and Amy, compete on a relay team. For the first race of the year, Daniela begins the r
Ad libitum [116K]

Answer:

A = {CBA, CAB, BCA, ACB}

Step-by-step explanation:

7 0
3 years ago
Help please!!! You are Miguel Cervantes de Navas y Colon, captain in the Royal Spanish Army in Sevilla in the year 1842
tiny-mole [99]

Answer:

There are 650 cannonballs


Step-by-step explanation:

If you look closely in the picture, you can see that:

  • 1st row has 1 ball
  • 2nd row has 4 balls
  • 3rd row has 9 balls
  • 4th row has 16 balls

etc. etc.

We can see that the number of balls is the square of the row number. There are a total of 12 rows. So, rest of the rows has:

  • 5th row has 25 balls
  • 6th row has 36 balls
  • 7th row has 49 balls
  • 8th row has 64 balls
  • 9th row has 81 balls
  • 10th row has 100 balls
  • 11th row has 121 balls
  • 12th row has 144 balls

If we add up all those, we get total number of balls:

1+4+9+16+25=36+49+64+81+100+121+144=650

There are 650 cannonballs



6 0
3 years ago
Read 2 more answers
A telemarketer is successful at getting people to donate money for her organization in 55% of all calls she makes. She must get
Tems11 [23]
An interesting twist to a binomial distribution problem.

Given:
p=55%=0.55 for probability of success in solicitation
x=4=number of successful solicitations
n=number of calls to be made
P(x,n,p)>=89.9%=0.899  (from context, it is >= and not =, which is almost impossible)

From context of question, all calls are assumed independent, with constant probability of success, so binomial distribution is applicable.

The number of successes, x, is then given by
P(x)=C(n,x)p^x(1-p)^{n-x}where
p=probability of success
n=number of trials
x=number of successesC(n,x)=\frac{n!}{x!(n-x)!}

Here we need n such that
P(x,n,p)>=0.899
given
x>=4, p=0.55, which means we need to find

Method 1: if a cumulative binomial distribution table is available, we can look up n=9,10,11 and find
P(x>=4,9,0.55)=0.834
P(x>=4,10,0.55)=0.898
P(x>=4,11,0.55)=0.939
So she must make (at least) 11 calls to make sure the probability of meeting her quota is 89.9% or more.

Method 2: using technology.
Similar to method 1, we can look up the probabilities directly, for n=9,10,11
P(x>=4,9,0.55)=0.834178
P(x>=4,10,0.55)=0.8980051
P(x>=4,11,0.55)=0.9390368

Method 3: using simple calculator
Here we need to calculate the probabilities for each value of n=10,11 and sum the probabilities of FAILURE S=P(0,n,0.55)+P(1,n,0.55)+P(2,n,0.55)+P(3,n,0.55)
so that the probability of success is 1-S.
For n=10,
P(0,10,0.55)=0.000341
P(1,10,0.55)=0.004162
P(2,10,0.55)=0.022890
P(3,10,0.55)=0.074603
So that
S=0.000341+0.004162+0.022890+0.074603
=0.101995
and Probability of getting 4 successes (or more) 
=1-S
=0.898005, missing target by 0.1%

So she will have to make 11 phone calls, bring up the probability to 93.9%.  The work is similar to that of n=10.
8 0
3 years ago
Work out the area of this quarter circle of radius 8 cm.<br> Give your answer in terms of pie
Bess [88]

16pi

Step-by-step explanation:

pi x r² = ans ÷ 4 = Answer for area

Pi×8²=64pi ÷ 4 = 16pi

3 0
3 years ago
Please help me! And please explain how to solve this. Especially questions B, C, and E
kati45 [8]
A. radical 76 is8.6 so  false
B. 3 radical 10 is 9.4  true
C. 4 radical 2 is 5.6 so false
D. radical 29 is 5.3 so true
E. 2 radical 50 is 14.14 so false
5 0
3 years ago
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