A random sample of 89 tourists in chattanooga showed that they spent an average of $2860 (in a week) with a standard deviation o
f $126; and a sample of 64 tourists in orlando showed that they spent an average of $2935 (in a week) with a standard deviation of $138. we are interested in determining if there is any significant difference between the average expenditures of all the tourists who visited the two cities.
2 answers:
Answer:
(a) 151 (b) 21430 (c) p value = 0.008 (d) We reject the null hypothesis and conclude that there is a significant difference between average expenditure of all tourist who visited the cities
Explanation:
Given that:
Let the random sample n₁ = 89
The average (x₁) = $2860
The standard deviation(σ) = $126
Random sample n = 64
The average (x₂) = $2935
The standard deviation(σ) = $138
Now,
(a) = The test degree of freedom = n₁ +n₂₂ - 2 = 89 +62 -2
= 151
Note kindly find an attached copy work to part of the solution of this exercise below
Answer:
The complete question is given in the explanation box below and the solutions to the problem is shown in the pictures attached herewith accordingly. Thank you.
Explanation:
a. Determine the degrees of freedom for this test.
b. Compute the test statistic.
c. Compute the p-value.
d. What is your conclusion? Let α = .05.
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