Based on the mass per unit length and the tension, the speed that the wave travels on this string is 519.615 m/s.
<h3>What is the speed?</h3><h3 />
The speed that the wave travels can be found as:
Velocity² = Tension / Mass per length
Solving gives:
Velocity² = 1,350 / 0.005
Velocity² = 270,000
Velocity = √270,000
= 519.615 m/s
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Answer:
V₁ = 5.6 m/s
V₂ = 7.2 m/s
V₃ = 8.8 m/s
Explanation:
Average velocity: Average velocity can be defined as the ratio of the total displacement to the total time taken. The S.I unit of Average velocity is m/s.
For the first 2 s,
V₁ = Δd₁/t
Where V₁ = Average velocity for the first 2 s
Where Δd₁= distance, t = time
Δd₁ = 25.6-14.4 = 11.2 m t = 2 s
V₁ = 11.2/2
V₁ = 5.6 m/s
For the second 2 s,
V₂ =Δd₂/t
Where V₂ = average velocity for the second 2 s.
Δd₂= 40-25.6 = 14.4 m, t= 2 s
V₂ = 14.4/2
V₂ = 7.2 m/s
For the last 2 seconds,
V₃ =Δd₃/t
Where V₃ = average velocity for the last 2 s
where Δd₃ = 57.6- 40 = 17.6 m, t = 2 s
V₃ = 17.6/2
V₃ = 8.8 m/s.
Answer:
Explanation:
The relationship between the refractive index and the critical angle is given as follows:
where,
η = refractive index = 1.67
θc = critical angle =?
Therefore,
