Answer: 88 Earth days
Explanation:
According to the Kepler Third Law of Planetary motion <em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.
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In other words, this law states a relation between the orbital period 
of a body (moon, planet, satellite) orbiting a greater body in space with the size 
of its orbit:
(1)
If we assume the orbit is circular and apply Newton's law of motion and the Universal Law of Gravity we have:
(2)
Where 
is the mass of the massive object and 
is the universal gravitation constant. If we assume constant and larger enough to consider really small, we can write a general form of this law:
(3)
Where is in units of Earth years, is in AU (<u>1 Astronomical Unit is the average distane between the Earth and the Sun)</u> and is the mass of the central object in units of the mass of the Sun.
This means when we are making calculations with planets in our solar system 
.
Hnece, in the case of Mercury:
(4)
Isolating :
(5)
(6)
This means the period of Mercury is 88 days.
Answer:
Explanation:
In order to solve this question we need to know that 
. Then we need to convert 4 minutes into seconds and cm into m. We can do that by multiplying the number of minutes by 60 (because there is 60 seconds in one minute) and dividing the number of cm by 100 (because there is 100 cm in one m). So.......
4min = 4 x 60s = 240s
300cm = 300/100 m = 3m
Now we know that distance = 300m, and that the time = 4min = 240s ⇒
⇒ 
Hey bud, Good to see you again!
Okay so lets get to work huh? :D
Circle - Railroad advance warnings, and some bus signs.
Octagon - Stop signs, and slow signs (for flooding on roads).
Triangle - People crossing, People working.
Square - parking, speed limit.
Diamond - Bicyclist, animal crossing.
Hope this helped. Have a great day!
Answer: initially the packet was ascending up with the balloon.
Taking upward as positive direction;
initial velocity, u = 4.9 m/s
final velocity = v m/s
initial height, h₁ = 245 m
final height, h₂ = 0
a = -9.8 m/s²
time taken = t seconds
s = ut + 0.5at²
⇒ (h₂-h₁) = ut + 0.5at²
⇒ 0-245 = 4.9t + 0.5×(-9.8)×t²
⇒ -245 = 4.9t - 4.9t²
⇒ 4.9t² -4.9t -245 =0
Solving it, we get t = 7.59s
v = u + at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/s
So velocity is 69.48 m/s downward
Explanation:
