Answer:
a. 2N
b. 12N
c. 20N
Explanation:
Dtaa given,
Weight of rock in air=10N
weight of rock in water =8N
a. When the rock is suspend in water, it will displace some water from thr container since Buoyant force is the acts upward and equals in magnitude to the volume of water displays,
The buoyant force is calculated as 10N-8N=2N
b. The scale reading will be the sum of the buoyant force and the weight of the container
scale reading =10N+2N=12N
c. When the rock rest at the bottom of the container, the weight of the rock(10N) is acting downward and the weight of the container also is acting downward. Hence the sum of the two weight gives the reading on the scale
scale reading=10N+10N=20N
The initial speed of the sled at the given height is 4.85 m/s.
<h3>Initial speed of the sled</h3>
Apply the principle of conservation of energy;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
- h is the vertical height reached
- g is acceleration due to gravity
v = √(2 x 9.8 x 1.2)
v = 4.85 m/s
Thus, the initial speed of the sled at the given height is 4.85 m/s.
Learn more about initial speed here: brainly.com/question/24493758
#SPJ1
Total number of Photons = 92.
Radius of the Nucleus = 7.4 x 10^-15 m
Charge of the nucleus = 1.6*10^-19.
Total charge q = 92 x 1.6*10^-19 = 147.2 x 10^-19
k = 9 x 10^9 N m^2 / C^2
Electric field charge E = kq / r^2
=> E = (9 x 10^9 x 147.2 x 10^-19) / (7.4 x 10^-15) ^2
=> (1324.8 x 10^-10) / 54.76 x 10^-30 => 24.19 x 10^20 N/C
