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Tatiana [17]
3 years ago
5

An object with a mass of 9 kg weighs 14.4 N on the Moon. What is the

Physics
2 answers:
erma4kov [3.2K]3 years ago
7 0

Answer:

1.6 m/s²

Explanation:

Weight equals mass times acceleration due to gravity.

F = mg

14.4 N = (9 kg) g

g = 1.6 m/s²

Luba_88 [7]3 years ago
7 0

You should give him the Brainliest.

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If 4,800 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the
Sloan [31]

Answer:

32000cm^3

Explanation:

Length L be base length

h be the height

Volume=V

V=L^2h

Surface area if box= L^2+4lh=4800

Solving for h

(4800-l^2/4L)=h

1200L-L^3/4=h

Substitute for h in V =L^2h

v=1200L-L^3/4

Differenting =1200-3*L^2/4=0

L=√(1600)=40

Substitute L=40

In V=1200L-L^3/4

Hence 1200*40-40^4/4=32000cm^3

5 0
3 years ago
Read 2 more answers
A body of mass 80kg was lifted vertically through a distance of 5.0 metres. Calculate the work done on the body. ( Acceleration
sleet_krkn [62]

Answer:

80×5×10=4000J

so therefore, work done on the body is 4000J

8 0
3 years ago
Where is the magnetic south pole compared to the geographical north pole?
Alex777 [14]

Currently, the magnetic south pole lies about ten degrees distant from the geographic north pole, and sits in the Arctic Ocean north of Alaska. The north end on a compass therefore currently points roughly towards Alaska and not exactly towards geographic north.

7 0
3 years ago
¿Qué nombre recibe un electrón que abandona el espacio interno del átomo dirigiéndose al exterior del átomo?
Alenkinab [10]

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7 0
2 years ago
A car sitting at a red light begins to accelerate at 2 m/s2 when the light turns green. It continues with this acceleration unti
jek_recluse [69]

Answer:

    x_total = 600 m

Explanation:

This is an exercise and kinematics, let's find the time it takes to reach the velocity  20 m / s

          v = v₀ + a t

           

as part of rest v₀ = 0

          t = v / a

          t = 20/2

          t = 10 s

let's find the distance traveled in this time

          x₁ = vo t + ½ a t2

          x₁ = 0 + ½ 2 10²

          x₁ = 100 m

The remaining time is

          t₂ = 35 - t

          t₂ = 35 - 10

          t₂ = 25 s

as in this range it has a constant speed

          v = x₂ / t₂

          x₂ = v t₂

          x₂ = 20  25

          x₂ = 500 m

the total distance traveled is

           x_total = x₁ + x₂

           x_total = 100 + 500

           x_total = 600 m

7 0
3 years ago
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