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lidiya [134]
3 years ago
7

The product of (1/2+3/4)(1/2-3/4)(i) and divided by (2-3i) is (multiplying complex numbers)

Mathematics
1 answer:
insens350 [35]3 years ago
6 0
B) because i think its that answer
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a botanist was measuring how tall her plant grew. after two weeks it had grown 9.62 inches. the second week alone it had grown 3
Elanso [62]

Answer:

6.5 inches

Step-by-step explanation:

Take the total 9.62 inches

Remove the 3.12 inches from the second week and there is your answer!

6 0
3 years ago
Math challenging and now math challenging me to challenge math
erastovalidia [21]

Answer:

$30

Step-by-step explanation:

Total amount paid by the hire purchase scheme:

$60 + 6 * $45 = $60 + $270 = $330

Total amount paid in just the cash price:

$300

Difference:

$330 - $300 = $30

3 0
3 years ago
You draw two cards from a standard deck of 52 cards. What is the probability of drawing a queen and then a king consecutively fr
Gelneren [198K]

Answer:

4/663

Step-by-step explanation:

There are 4 queens and 4 kings in a deck. Drawing a queen would be 4/52. Drawing a king afterwards with replacing the queen would be 4/51 because you took a queen but didn't replace that one queen card so the deck has only 51 cards left after you drew the queen. Drawing a queen would not affect your chance of drawing a king card, it will only affect the total number of cards left because you didn't replace the card afterwards. 4*4=16;52*51=2652. 16/2652 can be simplified to 4/663 by dividing 4 to both numbers. 16/4=4 and 2652/4=663. The probability of drawing a queen then a king without replacement would be 4/663.

3 0
3 years ago
Read 2 more answers
Prove by mathematical induction that 1+2+3+...+n= n(n+1)/2 please can someone help me with this ASAP. Thanks​
Iteru [2.4K]

Let

P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

P(1):\ 1 = \dfrac{1\cdot 2}{2}=1

So, the base case is ok. Now, we need to assume P(n) and prove P(n+1).

P(n+1) states that

P(n+1):\ 1+2+\ldots+n+(n+1) = \dfrac{(n+1)(n+2)}{2}=\dfrac{n^2+3n+2}{2}

Since we're assuming P(n), we can substitute the sum of the first n terms with their expression:

\underbrace{1+2+\ldots+n}_{P(n)}+n+1 = \dfrac{n(n+1)}{2}+n+1=\dfrac{n(n+1)+2n+2}{2}=\dfrac{n^2+3n+2}{2}

Which terminates the proof, since we showed that

P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}

as required

4 0
3 years ago
Iris wants to buy two necklaces, one for her sister and one for herself. The necklace for her sister costs $42.00, and the neckl
Genrish500 [490]

Answer:

$75.60

Step-by-step explanation:

First, find the total cost without tax:

42 + 28

= 70

Then, to find the price with sales tax, multiply this by 1.08:

70(1.08)

= 75.6

So, the total cost of her purchases was $75.60

4 0
3 years ago
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