The value of x from the given triangle is 32√3/3
<h3>SOH CAH TOA identity</h3>
In order to determine the value of x, first we need to determine the hypotenuse side of the smaller triangle.
sin 60 = 8√2/H
H = 8√2/sin60
H = 8√2 * 2/√3
H = 16√2/√3
H = 16√6/3
For the value of x, we will use the expression
sin45 = (16√6/3)/x
1/√2 = 16√6/3x
3x = 16√12
3x = 32√3
x = 32√3/3
Hence the value of x from the given triangle is 32√3/3
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-3
Multiply 3 times -1 to get -3
Answer:
three-eighths multiplied by the difference of one and one-third.
Step-by-step explanation:
Convert equation to words
3/8 = three-eighths
x = multiplied
1 - 1/3 = difference of one and 1/3
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Answer:
The answer to the question is
The kinds of polygons that could be Diedre's quadrilateral are rectangle and square
Step-by-step explanation:
We note the conditions of the polygon as thus
Number of sides = 4, Which include trapezoid, square, rectangle
Size of angles = 90 ° which eliminates trapezoid
Sizes of opposite sides = Equal opposite sides, includes square and rectangle
With the above we conclude that the possible polygons in Diedre's quadrilateral are rectangle and square