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Shalnov [3]
2 years ago
9

182632929236+188274739393974473

Mathematics
2 answers:
Lorico [155]2 years ago
7 0

Answer:

Exact Form: 188274922026903709

Decimal Form: 1.88274922*10^17

Step-by-step explanation:

Anna35 [415]2 years ago
6 0

Answer:

the answer id

188274922026903709

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As Saturn revolves around the sun, it travels at a speed of approximately 6 miles per second. Convert this speed to miles per mi
leva [86]

Answer:

The answer is 21,600. If it travels 6 miles per second that in a minute it would travel 360 miles. You multilpy 360 times 6 and you get your answer of 21,600 miles.

Step-by-step explanation:

5 0
3 years ago
A number is multiplied by 2, and then 5 is subtracted. The result is 43.
irga5000 [103]

Answer: The answer is 7.

5 0
2 years ago
Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int
Talja [164]

Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula :A=P(1+r)^t

A=5000(1+0.04)^3

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{2})^{2 \times 3}

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{4})^{4 \times 3}

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula :A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{12})^{12 \times 3}

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

8 0
3 years ago
Suppose you want to solve the equation 2a + 2b= 2a, where a and b are nonzero real numbers. Describe the solution to this equati
Anna11 [10]
This equation has no solution where 'a' and 'b'
are both non-zero real numbers.

You said                                 2a + 2b = 2a

Subtract 2a from each side:         2b = 0

'b' must be zero.

And it doesn't matter what the value of 'a' is.
As long as b=0, 'a' can be any number.
5 0
3 years ago
Aidan has 20 ft of fence with which to build a rectangular dog run. What is the maximum area he can enclose? Enter your answer i
irina1246 [14]
<h2>Maximum area is 25 m²</h2>

Explanation:

Let L be the length and W be the width.

Aidan has 20 ft of fence with which to build a rectangular dog run.

         Fencing = 2L + 2W  = 20 ft

                     L + W = 10

                      W = 10 - L

We need to find what is the largest area that can be enclosed.

     Area = Length x Width

      A = LW

       A = L x (10-L) = 10 L - L²

For maximum area differential is zero

So we have

      dA = 0

      10 - 2 L = 0

        L = 5 m

      W = 10 - 5 = 5 m

Area = 5 x 5 = 25 m²

Maximum area is 25 m²

7 0
3 years ago
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