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ollegr [7]
3 years ago
12

How many ounces are in a square meter?

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0
3.007 ounces per square meter
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A and B are bounded non-empty subsets of R. For inf(A) to be less than or equal to inf(B), which of the following conditions mus
nirvana33 [79]

Answer:

a) must be met

Step-by-step explanation:

We have two conditions:

a) For every b\in B and \epsilon>0, there exists a\in A, such that a.

b) There exists a\in A and b\in B such that  a.

We will prove that conditon a) is equivalent to inf(A)\leq inf(B)

If a) is not satisfied, then it would exist b\in B and \epsilon >0 such that, for every a\in A, a\geq b+\epsilon. This implies that b+\epsilon is a lower bound for A and in consequence

inf(A)\geq b+\epsilon > b\geq inf(B)

Then, inf(A) \leq inf(B) implies a).

If inf(A) \leq inf(B) is not satisfied then, inf(A) > inf(B) and in consequence exists b\inB such that b-inf(A)=\epsilon >0. Then b-\epsilon=inf(A) and, for every a\in A,

b-\epsilon =inf(A)\leq a.

So, a) is not satisfied.

In conclusion, a) is equivalent to inf(A)\leq inf(B)

Finally, observe that condition b) is not an appropiate condition to determine if inf(A)\leq inf(B) or not. For example:

  • <u>A={0}, B={1}</u>. b) is satisfied and inf(A)=0
  • <u>A={0}. B={-1,1}</u>. b) is satisfied and inf(A)=0>-1=inf(B)

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Ignoring color, what kind of symmetry does the pinwheel have? A. rotational symmetry B. line symmetry C. both rotational and lin
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The answer is a because there isn't any line of symmetry
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What is m∠D ?<br><br> Enter your answer in the box. __°
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Check the picture below.

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Step-by-step explanation:

so that is easy it is rise over run!!!

y2-y1 over x2-x1!!! look at picture!!!

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10% * $230.00 = $23.00

The discount is $23.00.

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Of course, you know that 10% expressed as a decimal is 0.10. Many calculators will calculate percentages directly. If yours doesn't, you can use the decimal equivalent. If you recognize that multiplying by 1/10 simply shifts the decimal point to the left one place, you can do the arithmetic in your head.
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