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34kurt
3 years ago
9

What is 7+7. i need an answer now

Mathematics
2 answers:
trasher [3.6K]3 years ago
5 0
It’s 14. You can count on your fingers to
lianna [129]3 years ago
3 0
7+7=14. You can draw pictures, count on your hands, etc.

Hope this helps!
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If preimage is (0, 1) . (4, 0), (4, 1) , what are the points after a translation of 3 units up and then a reflection over the -a
yulyashka [42]

Answer:

(0, 4) (-4, 3) (-4, 4)

Step-by-step explanation:

Translation rules:

Units UP - Add to the y-coordinate.

Units DOWN - Subtract from the y-coordinate.

Units RIGHT - Add to the x-coordinate.

Units LEFT - Subtract from the x-coordinate.

--------------------------------------------------------------------------------------------------------------

In this case, the word problem is asking for the points after a translation of 3 units up.

(x, y+3)

(0,1) → (0,4)

(4,0) → (4,3)

(4,1) → (4,4)

--------------------------------------------------------------------------------------------------------------Now it's time to reflect the new points over the y-axis.

When reflecting over the y-axis, the y-coordinate remains the same, but the x-coordinate becomes the opposite value. (-x, y)

(0,4) → (0,4)

(4,3) → (-4,3)

(4,4) → (-4,4)

3 0
3 years ago
Which number goes in the box to make a true equation?<br> ]X 10 = 42.000
kherson [118]

Answer:

x=4200

Step-by-step explanation:

10x=42000

x=4200

5 0
3 years ago
write an equation of the line that passes through (-1, 4) and is perpendicular to the line y=-1/3x+3​
gladu [14]

Answer:

y= 3x + 7                                                                                                            Step-by-step explanation:

y= -1/3x+3 (so, gradient of this line is -1/3).

formula: gradient of line one x gradient of line two= -1 (applies for 2 perpendicular lines only).

So, m1 x -1/3= -1

m1= (\frac{-1}{\frac{-1} {3} })

m1= 3 (gradient of perp line)

y=mx+c

4= 3 x -1 + c

7=c

therefore, y=3x+7 (eqn of the line perp to y=-1/3x+3)

4 0
3 years ago
Someone help and plz make sure it’s right plz :)
Stolb23 [73]

Answer:

6.3

Step-by-step explanation:

square root of (14.9k^2 - 13.5k^2)

7 0
3 years ago
If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's ru
aleksandrvk [35]

Answer:

Step-by-step explanation:

If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's rule to compute the limit of the sequence given by

bn=(n)^(5.6/n).

a)

L =  \lim_{n \to \infty} b_n \\\\\\L= \lim_{n \to \infty} n^{\frac{5.6}{n} }

Log on both sides

In (L) =  \lim_{n \to \infty} In (n)^{\frac{5.6}{n} }\\\\= \lim_{n \to \infty} \frac{5.6}{n} In(n)

=5.6 \lim_{n \to \infty} \frac{d}{dn}  In(n)/\frac{d}{dn} (n)\\\\=5.6 \lim_{n \to \infty} \frac{1}{n} /1 \\\\=5.6 \lim_{n \to \infty} \frac{1}{n} \\\\=5.6 \times 0\\\\In(L) =0\\\\L=e^0\\\\L=1

\therefore  \lim_{n \to \infty} (n)^{\frac{5.6}{n} =1

5 0
3 years ago
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