Answer:
The special price of 1 hardcover book = $13
The special price of 1 paperback book = $6
Step-by-step explanation:
Here, let us assume the special price of 1 hardcover book = $ m
and the the special price of 1 paperback book = $ n
Now, the price of 12 hardcover books = 12 x ( Price of 1 hardcover) = 12 m
and the price of 73 paperback books = 73 x ( Price of 1 paperback) = 73 n
Also, The price paid for 12 hardcover and 73 paperback books is $594
⇒ 12 m + 73 n = 594 ....... (1)
Similarly:
The price of 11 hardcover books = 11 x ( Price of 1 hardcover) = 11 m
The price of 87 paperback books = 87 x ( Price of 1 paperback) = 87 n
Also, The price paid for 11 hardcover and 87 paperback books is $665.
⇒ 11 m + 87 n = 665 ....... (2)
Now, solving both equation for the value of m and n , we get:
12 m + 73 n = 594 x 11
11 m + 87 n = 665 x (-12)
we get: 132 m + 803 n = 6534
- 132 m - 1044 n = - 7980
adding both equation, we get:
132 m + 803 n - 132 m - 1044 n = - 7980 + 6534
or, - 241 n = - 1446
or, n = 1446/241 = 6, or n = 6
Now, Substituting n = 6 in 12 m + 73 n = 594 ,
we get: 12 m + 73 ( 6) = 594, m = 13
Hence, The special price of 1 hardcover book = $13
and The special price of 1 paperback book = $6
