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Diano4ka-milaya [45]
3 years ago
15

Lewis needed to find the difference in lengths between the hypotenuse and the longest leg of this triangle. His work is shown be

low. Triangle A B C. Side B C is 16 and side A C is 12. Hypotenuse A B is labeled c. 12 squared + 16 squared = c squared. 144 + 256 = c squared. 400 = c squared. StartRoot 400 EndRoot = c. 200 = c. Difference: 200 minus 12 = 188. What errors did Lewis make? Check all that apply. He simplified StartRoot 400 EndRoot incorrectly. It should be 20 instead of 200. He found the difference between the hypotenuse and the short leg instead of the long leg. He evaluated 12 squared incorrectly. It should be 12 (2) = 24. He evaluated 16 squared incorrectly. It should be 16 (2) = 32. He should not have taken the square root of each side to get rid of the exponent.
Mathematics
2 answers:
Rus_ich [418]3 years ago
8 0

Answer: A and

Step-by-step explanation: the other

dimaraw [331]3 years ago
7 0

Answer:

The answer is first and last

Step-by-step explanation:

Edge2020

im not gonna explain cuz some    other guy got it wrong and  im just answering for anyone  who needs it

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The 3 side lengths of a right-
Gekata [30.6K]

Answer: the area of the triangle = 10.5 cm²

Step-by-step explanation:

Let 3x=a, 4x=b, 5x=c.

Hence,

P=2*(a+b+c)

36=2*(3x+4x+5x)

36=2*12x

36=24x

Divide both parts of the equation by 24:

1.5 cm=x

a=3x

a=3*1.5

a=4.5 cm

b=4x

b=4*1.5

b=6 cm

c=5x

c=5*1.5

c=7.5 cm

\displaystyle\\S=\frac{a*b}{2} \\\\S=\frac{4.5*6}{2} \\\\S=3.5*3\\\\S=10.5\  cm^2

3 0
2 years ago
Find the value of x​
steposvetlana [31]

Answer:

x=3

Step-by-step explanation:

6x+6/32=9x-9/24

144x+144=288x-288

144x=288x-432

-144x=-432

Therefore, x=3

6 0
3 years ago
Read 2 more answers
11.Write the equations of linear and exponential functions that pass through the points (0,9) and (1,3)
Schach [20]

9514 1404 393

Answer:

  y = -6x +9

  y = 9·(1/3)^x

Step-by-step explanation:

In each case, the y-intercept is 9.

Linear

The slope is rise/run = (3-9)/(1-0) = -6, so the equation is ...

  y = mx + b . . . . . . . slope m, intercept b

  y = -6x +9

Exponential

The ratio of value at x=1 to that at x=0 is 3/9 = 1/3. That is the "growth factor," so the equation is ...

  y = 9·(1/3)^x

7 0
3 years ago
Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).
Elan Coil [88]

Answer: \int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = \left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0

Then, replacing with point P and normal vector n:

36(x-5) + 20(y-0) + 45(z-0) = 0

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

z = \frac{180-36x-20y}{45}

When z = 0:

y = 9 + \frac{-9x}{5}

When z=0 and y=0:

x = 5

Then, triple integral is:

\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx

Calculating:

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx

\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0  {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx

\frac{1}{45} \int\limits^5_0  {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4}  } \, dx

\frac{1}{45} [30375-60750+118462.5-39150]

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0
3 years ago
I REALLY NEED HELP PLS​
TEA [102]

Answer:

Step-by-step explanation:

100+2x+40=180(sum of interior angle of a triangle)

140+2x=180

2x=180-140

2x=40

x=40/2

x=20

8 0
2 years ago
Read 2 more answers
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