All categories

3 years ago

Find the value of 2^-3 x 3^-2

Mathematics

2 answers:

Inga [223]3 years ago

7 0

Answer:

$\frac{1}{72}$

Step-by-step explanation:

Using the rule of exponents

$a^{-m}$ ⇔ $\frac{1}{a^{m} }$ , then

$2^{-3}$ = $\frac{1}{2^{3} }$ = $\frac{1}{8}$ and

$3^{-2}$ = $\frac{1}{3^{2} }$ = $\frac{1}{9}$

Hence

$2^{-3}$ × $3^{-2}$

= $\frac{1}{8}$ × $\frac{1}{9}$

= $\frac{1(1)}{8(9)}$

= $\frac{1}{72}$

anastassius [24]3 years ago

4 0

Answer:

0.01388888888 or .0139

Step-by-step explanation:

.125*.11111111111=0.01388888888 or .0139

You might be interested in

Can you please help I have no idea how to I’m stuck

Scrat [10]

Report this answered this on accident ........

5 0

3 years ago

This is confusing please help

stira [4]

Step-by-step explanation:

since we are using Pythagoras

c² = a² + b²

with c being the Hypotenuse (the baseline opposite of the 90° angle),

you want to get the expression

y² = 3² + 3²

so, you pick the ² and put it next to the y left of the "=" sign.

and to the right of the "=" sign you put 3, ², +, 3, ²

3 0

2 years ago

50 x 10⁴ what dose that equal

Alborosie

Answer:

500000

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Look at the figure shown below:

miv72 [106K]

The answer is C. Using ASA postulate, prove that triangles PQS and PRS are similar triangles

7 0

2 years ago

Read 2 more answers

Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then

tino4ka555 [31]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are <em>x</em> number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

$\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x$

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

$\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x$

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

$\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x$

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

$\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x$

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

$\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x$

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of <em>x</em> as follows:

$\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}$

Compute the number of candies in the sixth jar as follows:

$\text{Number of candies in the 6th jar}=\frac{63}{32}x\\$

$=\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42$

Thus, the number of candies in the sixth jar is 42.

4 0

3 years ago