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3 years ago

Find the value of 2^-3 x 3^-2

Mathematics

2 answers:

Inga [223]3 years ago

7 0

Answer:

$\frac{1}{72}$

Step-by-step explanation:

Using the rule of exponents

$a^{-m}$ ⇔ $\frac{1}{a^{m} }$ , then

$2^{-3}$ = $\frac{1}{2^{3} }$ = $\frac{1}{8}$ and

$3^{-2}$ = $\frac{1}{3^{2} }$ = $\frac{1}{9}$

Hence

$2^{-3}$ × $3^{-2}$

= $\frac{1}{8}$ × $\frac{1}{9}$

= $\frac{1(1)}{8(9)}$

= $\frac{1}{72}$

anastassius [24]3 years ago

4 0

Answer:

0.01388888888 or .0139

Step-by-step explanation:

.125*.11111111111=0.01388888888 or .0139

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What is the probability of picking a blue coin out of a bag that contains 5 blue and 10 red coins

Neko [114]

the probability is 5/15 or 1/3.

You add up all the coins (5+10=15) and since there’s 5 blue coins in the bag, you put 5 over 15. You simplify that to 1/3.

hope this helped !!

6 0

3 years ago

MATH HELP PLEASE!!! PLEASE HELP!!!

grandymaker [24]

The answer is: [C]: " f(c) = $\frac{9}{5}$ c + 32 " .
________________________________________________________

Explanation:
________________________________________________________
Given the original function:

" c(y) = (5/9) (x − 32) " ; in which "x = f" ; and "y = c(f) " ;
________________________________________________________
→ Write the original function as: " y = (5/9) (x − 32) " ;

Now, change the "y" to an "x" ; and the "x" to a "y"; and rewrite; as follows:
________________________________________________________
x = (5/9) (y − 32) ;

Now, rewrite THIS equation; by solving for "y" ; in terms of "x" ;
_____________________________________________________
→ That is, solve this equation for "y" ; with "c" as an "isolated variable" on the
"left-hand side" of the equation:

We have:

→ x = " ( $\frac{5}{9}$ ) * (y − 32) " ;

Let us simplify the "right-hand side" of the equation:
_____________________________________________________

Note the "distributive property" of multiplication:
__________________________________________
a(b + c) = ab + ac ; AND:

a(b – c) = ab – ac .
__________________________________________

As such:
__________________________________________

" ( $\frac{5}{9}$ ) * (y − 32) " ;

= [ ( $\frac{5}{9}$ ) * y ] − [ ( $\frac{5}{9}$ ) * (32) ] ;

= [ ( $\frac{5}{9}$ ) y ] − [ ( $\frac{5}{9}$ ) * ( $\frac{32}{1})$ " ;

= [ ( $\frac{5}{9}$ ) y ] − [ ( $\frac{(5*32)}{(9*1)}$ ] ;

= [ ( $\frac{5}{9}$ ) y ] − [ ( $\frac{(160)}{(9)}$ ] ;

= [ ( $\frac{5y}{9}$ ) ] − [ ( $\frac{(160)}{(9)}$ ] ;

= [ $\frac{(5y-160)}{9}$ ] ;
_______________________________________________
And rewrite as:

→ " x = $\frac{(5y-160)}{9}$ " ;

We want to rewrite this; solving for "y"; with "y" isolated as a "single variable" on the "left-hand side" of the equation ;

We have:

→ " x = $\frac{(5y-160)}{9}$ " ;

↔ " $\frac{(5y-160)}{9}$ = x ;

Multiply both sides of the equation by "9" ;

9 * $\frac{(5y-160)}{9}$ = x * 9 ;

to get:

→ 5y − 160 = 9x ;

Now, add "160" to each side of the equation; as follows:
_______________________________________________________

→ 5y − 160 + 160 = 9x + 160 ;

to get:

→ 5y = 9x + 160 ;

Now, divided Each side of the equation by "5" ;
to isolate "y" on one side of the equation; & to solve for "y" ;

→ 5y / 5 = (9y + 160) / 5 ;

to get:

→ y = (9/5)x + (160/5) ;

→ y = (9/5)x + 32 ;

→ Now, remember we had substituted: "y" for "c(f)" ;

Now that we have the "equation for the inverse" ;
→ which is: " (9/5)x + 32" ;

Remember that for the original ("non-inverse" equation); "y" was used in place of "c(f)" . We have the "inverse equation"; so we can denote this "inverse function" ; that is, the "inverse" of "c(f)" as: "f(c)" .

Note that "x = c" ;
_____________________________________________________
So, the inverse function is: " f(c) = (9/5) c + 32 " .
_____________________________________________________

The answer is: " f(c) = $\frac{9}{5}$ c + 32 " ;
_____________________________________________________
→ which is:

→ Answer choice: [C]: " f(c) = $\frac{9}{5}$ c + 32 " .
_____________________________________________________

6 0

3 years ago

At the dealership where she works, Sade fulfilled 3/10 of her quarterly sales goal in January and another 1/10 of her sales goal

skelet666 [1.2K]

Hi There!

----------------------------------------

Problem #1:

At the dealership where she works, Sade fulfilled 3/10 of her quarterly sales goal in January and another 1/10 of her sales goal in February. What fraction of her quarterly sales goal had Sade reached by the end of February?

3/10 + 1/10 = 4/10

4/10 of her goal.

----------------------------------------

Problem #2:

Shane has been monitoring his mileage. According to last week's driving log, he drove 1/10 of a mile in his car and 9/10 of a mile in his truck. How far did Shane drive last week in all?

1/10 + 9/10 = 10/10 = 1

Shane drove 1 mile.

----------------------------------------

Problem #3:

For a class experiment, Vina's class weighed a log before and after subjecting it to termites. Before subjecting it to termites, the log weighed 7/10 of a pound. After the termites, the log weighed 3/10 of a pound. How much weight did the termites take from the log?

7/10 - 3/10 = 4/10

The termites took 4/10 pound away from the log.

----------------------------------------

Hope This Helps :)

6 0

3 years ago

A population proportion is . A sample of size will be taken and the sample proportion will be used to estimate the population pr

padilas [110]

Complete Question:

A population proportion is 0.4. A sample of size 200 will be taken and the sample proportion p will be used to estimate the population proportion. Use z- table Round your answers to four decimal places. Do not round intermediate calculations. a. What is the probability that the sample proportion will be within ±0.03 of the population proportion? b. What is the probability that the sample proportion will be within ±0.08 of the population proportion?

Answer:

A) 0.61351

Step-by-step explanation:

Sample proportion = 0.4

Sample population = 200

A.) proprobaility that sample proportion 'p' is within ±0.03 of population proportion

Statistically:

P(0.4-0.03<p<0.4+0.03)

P[((0.4-0.03)-0.4)/√((0.4)(.6))/200 < z < ((0.4+0.03)-0.4)/√((0.4)(.6))/200

P[-0.03/0.0346410 < z < 0.03/0.0346410

P(−0.866025 < z < 0.866025)

P(z < - 0.8660) - P(z < 0.8660)

0.80675 - 0.19325

= 0.61351

B) proprobaility that sample proportion 'p' is within ±0.08 of population proportion

Statistically:

P(0.4-0.08<p<0.4+0.08)

P[((0.4-0.08)-0.4)/√((0.4)(.6))/200 < z < ((0.4+0.08)-0.4)/√((0.4)(.6))/200

P[-0.08/0.0346410 < z < 0.08/0.0346410

P(−2.3094 < z < 2.3094)

P(z < -2.3094 ) - P(z < 2.3094)

0.98954 - 0.010461

= 0.97908

6 0

3 years ago

Find the volume of a right circular cone that has a height of 18.9 in and a base with a

Dmitriy789 [7]

Answer:

The volume of the cone is:

112.6 cubic inches.

Step-by-step explanation:

You should know that the volume of a straight circular cone is equal to:

Cone volume = (1/3) PI * r ^ 2 * h

Where:

r = radius.

h = height.

Since the radius and diameter are not provided in the exercise but the circumference, the circumference formula should be used and the diameter must be cleared:

Circumference = PI * Diameter.

When clearing you get:

Diameter = circumference / PI

By replacing the data you get:

Diameter = 15 inches / PI
Diameter = 4.77 inches.

Since the radius is equal to half the diameter, then the diameter is equal to 2,385 inches, now having the value of radius we proceed to replace in the volume formula:

Cone volume = (1/3) PI * 2.385 in^2 * 18.9 in
Cone volume = 112.581541 in^3
Cone volume = 112.6 in^3

3 0

2 years ago