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frosja888 [35]
3 years ago
6

Find the value of 2^-3 x 3^-2

Mathematics
2 answers:
Inga [223]3 years ago
7 0

Answer:

\frac{1}{72}

Step-by-step explanation:

Using the rule of exponents

a^{-m} ⇔ \frac{1}{a^{m} }, then

2^{-3} = \frac{1}{2^{3} } = \frac{1}{8} and

3^{-2} = \frac{1}{3^{2} } = \frac{1}{9}

Hence

2^{-3} × 3^{-2}

= \frac{1}{8} × \frac{1}{9}

= \frac{1(1)}{8(9)}

= \frac{1}{72}

anastassius [24]3 years ago
4 0

Answer:

0.01388888888 or .0139

Step-by-step explanation:

.125*.11111111111=0.01388888888 or .0139

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