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Gemiola [76]
3 years ago
10

If h=xtan60* and h=(40-x)tan30* how do i find h

Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

Answer simultaneously :)

Input equation 1 into equation 2

xtan60*=(40-x)tan30*

xtan60/tan30= (40-x)

3x = 40-x

4x = 40

x = 10

Hope this helps :) !

I'd appreciate if you'd mark my answer brainliest because ive been stuck on the same rank for wayyy too long :(

Goodluck! :)

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For the function y = -2+5sin(pi/12(x-2)), what is the maximum value?
myrzilka [38]
To get the function y = <span>-2+5sin(pi/12(x-2)), the maximum value can be determined by differentiating the function and equating it to zero. The value of x will give the maximum value of the function.
dy/dx = 5 cos (pi/12 (x-2)) (pi/12)
dy/dx = 5 pi/12 cos(pi/12 (x-2))

Equate to zero</span>:
<span>5 pi/12 cos(pi/12 (x-2)) =0
pi/12 (x-2) = 3pi/2
x = 8

Substituting,
y= -2 + 5sin( pi/12 (8-2)
y = -1.86
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2 years ago
Factor the expression. K^2+kf-2f^2
evablogger [386]

Answer:

cant factor something that is not like terms its the same answer

Step-by-step explanation:

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2 years ago
Ms. Fong class chose their favorite foods. 1/3 of the students chose hamburgers and 3/8 of the students chose pizza. What fracti
svetoff [14.1K]

1/3  chose hamburger and 3/8 chose pizza

add them together

1/3 + 3/8

get a common denominator of 24

1/3 *8/8 + 3/8 *3/3

8/24 + 9/24

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Choice D

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2 years ago
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How are the coordinates of a new point found if the point is reflected through the line y = x? How are the coordinates of the ne
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The a point is refrected through the line y = x, the new point is found by interchanging the x and y-cordinate of the original point. i.e. if the original point is (a, b) and is refrected through the line y = x, the new point will be (b, a).
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Someone please help me with this question !!!!
Lyrx [107]

Answer:

34.3 in, 36.3 in

Step-by-step explanation:

From the question given above, the following data were obtained:

Hypothenus = 50 in

1st leg (L₁) = L

2nd leg (L₂) = 2 + L

Thus, we can obtain the value of L by using the pythagoras theory as follow:

Hypo² = L₁² + L₂²

50² = L² + (2 + L)²

2500 = L² + 4 + 4L + L²

2500 = 2L² + 4L + 4

Rearrange

2L² + 4L + 4 – 2500 = 0

2L² + 4L – 2496 = 0

Coefficient of L² (a) = 2

Coefficient of L (n) = 4

Constant (c) = –2496

L = –b ± √(b² – 4ac) / 2a

L = –4 ± √(4² – 4 × 2 × –2496) / 2 × 2

L = –4 ± √(16 + 19968) / 4

L = –4 ± √(19984) / 4

L = –4 ± 141.36 / 4

L = –4 + 141.36 / 4 or –4 – 141.36 / 4

L = 137.36/ 4 or –145.36 / 4

L = 34.3 or –36.3

Since measurement can not be negative, the value of L is 34.3 in

Finally, we shall determine the lengths of the legs of the right triangle. This is illustrated below:

1st leg (L₁) = L

L = 34.4

1st leg (L₁) = 34.3 in

2nd leg (L₂) = 2 + L

L = 34.4

2nd leg (L₂) = 2 + 34.3

2nd leg (L₂) = 36.3 in

Therefore, the lengths of the legs of the right triangle are 34.3 in, 36.3 in

5 0
3 years ago
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