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Gemiola [76]
3 years ago
10

If h=xtan60* and h=(40-x)tan30* how do i find h

Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

Answer simultaneously :)

Input equation 1 into equation 2

xtan60*=(40-x)tan30*

xtan60/tan30= (40-x)

3x = 40-x

4x = 40

x = 10

Hope this helps :) !

I'd appreciate if you'd mark my answer brainliest because ive been stuck on the same rank for wayyy too long :(

Goodluck! :)

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Answer:

No

Step-by-step explanation:

First solve both equations:

1) 9x = 5x + 4

Simplifying

9x = 5x + 4

Reorder the terms:

9x = 4 + 5x

Solving

9x = 4 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.

9x + -5x = 4 + 5x + -5x

Combine like terms: 9x + -5x = 4x

4x = 4 + 5x + -5x

Combine like terms: 5x + -5x = 0

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4x = 4

Divide each side by '4'.

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Simplifying

x = 1

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14x = 4 (divide both sides by 14 to get x)

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As you can see, the value of x in the second equations is less than one, therefore making these algebraic equations not equivalent.

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2 years ago
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coldgirl [10]

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3 years ago
The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of
ivanzaharov [21]
<h2>Answer:</h2>

R_2  is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors R_1 and R_2 connected together in parallel, the total resistance R_T is given by;

\frac{1}{R_T} = \frac{1}{R_1}  + \frac{1}{R_2}              ---------(i)

<em>Make </em>R_2<em> subject of the formula;</em>

=> \frac{1}{R_2} = \frac{1}{R_T}  - \frac{1}{R_1}  

=> \frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}

=>   {R_2} = \frac{R_TR_1}{R_1 - R_T}       ---------------(ii)

From the question,

R_1 = 6Ω

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Substitute these values into equation (ii) as follows;

=> {R_2} = \frac{2*6}{6 - 2}

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R_2 = 3Ω

Therefore, the value of R_2 = 3 ohms or R_2 = 3Ω

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