The answer is 3/4 and it was already simplified
I’m pretty sure it’s y if not I’m sorry
The answers are 3/8 and 1/6.
There are 8 possible outcomes in the sample space for flipping 3 coins. Of those, 3 include two heads and 1 tail. This makes the probability 3/8.
Choosing a quarter for the first coin is 3/10, since there are 3 quarters out of 10 coins. After this, choosing a dime is given by 5/9, since there are 5 dimes out of 9 coins left:
3/10(5/9) = 15/90 = 1/6
5/10 is equal to 25/50
I ts because you multiply 5x5 to get 25 and do the same to the denominator so 10x5 is equal to 50 so 25/50 is the answer.
Answer: i think method of least squares (d.)
Step-by-step explanation: i’m pretty sure this is correct because mean is good for unimodal, unskewed histograms, median is good for unimodal asymmetrical histograms, and mode is good for bimodal histograms. i’m not sure tho bcs i learned this in statistics.