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Ket [755]
3 years ago
6

There were several sunny days this year before my birthday. Since my birthday, there have been 171717 more sunny days. My birthd

ay was not a sunny day. Altogether, there have been 838383 sunny days this year. How many sunny days were there before my birthday? sunny days
Mathematics
1 answer:
Lesechka [4]3 years ago
4 0

Answer:

66 sunny days before birthday

Step-by-step explanation:

Total sunny days after birthday = 17

Total sunny days in year = 83

Birthday was not sunny

Total sunny days before birthday = 83 -17

                                                       = 66 sunny days

Read more on Brainly.in - https://brainly.in/question/6937259#readmore

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Can anybody answer this??
Arturiano [62]

Answer:

(<em>x</em>, <em>y</em>) represent coordinates, <em>m</em> represents slope, and <em>b</em> represents the y-intercept

3 0
3 years ago
If f(x) = -(-2x - 5), what is f(-5)?
sammy [17]

Answer:

f(-5)=-5

Step-by-step explanation:

f(-5)= -((-2)(-5)-5)

     = -(10-5)

     = -(5)

     = -5

4 0
3 years ago
Read 2 more answers
Owen is reading a science fiction book is 558 pages long if he reads 28Pages each day How many days will it take him to read the
hichkok12 [17]

Answer:

20 days

Step-by-step explanation:

7 0
3 years ago
Using the transformation T : (x, y) → (x + 2, y + 1), find the distance named Find C'A'
deff fn [24]
We have that
<span>A' (2,1)

C(-2,2)-------> </span>Using the transformation-----> C' (-2+2,2+1)----> C' (0,3)

with 
A' (2,1) and C' (0,3)
find the distance <span>C'A'

d=</span>√[(y2-y1)²+(x2-x1)²]----> d=√[(3-1)²+(0-2)²]----> d=√8----> 2√2 units

the answer is
the distance C'A' is 2√2 units

5 0
3 years ago
Ten people at a party decide to compare ages. Five people are 30 years old, three are 32, one is 31, and one is 65.
horrorfan [7]
Given:
Ten People
5 people = 30 years old
3 people = 32 years old
1 person = 31 years old
1 person = 65 years old

We need to arrange the ages in order from least to greatest.

30, 30, 30, 30, 30, 31, 32, 32, 32, 65 
65 is the outlier. 

A.) mean age without the outlier. count of the numbers : 9
5 x 30 =    150
1 x 31 =      31
3 x 32 =<u>      96</u>
total age  277
÷ # of pax<u>    9</u>
mean         30.77 round to the nearest tenth 30.80

b.) Standard deviation:
We need to calculate variance first:
5 pax : 30 - 30.80 = - 0.80 ⇒ -0.80² = 0.64 * 5pax = 3.20
1 pax : 31 - 30.80 =   0.20 ⇒  0.20²  = 0.04 * 1pax = 0.04
3 pax : 32 - 30.80 =   1.20 ⇒  1.20² = 1.44 * 3 pax = 4.32

Variance : (3.20 + 0.04 + 4.32) / 9 pax = 7.56 / 9 = 0.84

Standard deviation is simply the square root of the variance.

Standard deviation = √0.84 = 0.916 

0.916 round to nearest hundredths is 0.92
0.916 round to nearest tenths is 0.90
8 0
3 years ago
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