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3 years ago

6

There were several sunny days this year before my birthday. Since my birthday, there have been 171717 more sunny days. My birthd

ay was not a sunny day. Altogether, there have been 838383 sunny days this year. How many sunny days were there before my birthday? sunny days

1 answer:

Lesechka [4]3 years ago

4 0

Answer:

66 sunny days before birthday

Step-by-step explanation:

Total sunny days after birthday = 17

Total sunny days in year = 83

Birthday was not sunny

Total sunny days before birthday = 83 -17

= 66 sunny days

Read more on Brainly.in - https://brainly.in/question/6937259#readmore

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An electronic system has each of two different types of components in joint operation. Let X and Y denote the lengths of life, i

AURORKA [14]

Answer:

a

The average cost is $E(C) = 66$

b

The standard deviation of cost is $\sigma = 9.798$

Step-by-step explanation:

From the question we are told that

$E(X) = 4$

$E(Y) = 2$

$E(X^2) = 24$

$E(Y^2) = 8$

The cost of replacing the two component is C = 50 + 2 X + 4 Y

The variance of X is mathematically represented as

V(X) = $E(X^2) - [E(X)]^2$

Substituting values

$V[X] = 24 - 4^2$

$V[X] =8$

The variance of Y is mathematically represented as

V(Y) = $E(Y^2) - [E(Y)]^2$

Substituting values

$V[Y] = 8 - 2^2$

$V[X] =4$

The average of replacing the two component is

$E(C) = 2 * E(X) + 4* E(Y)$

substituting value

$E(C) = 50 + 2 * (4) + 4* (2)$

$E(C) = 66$

The variance of replacing the two component is

$V(C) = V(50 + 2X +4Y)$ Note: The variance of constant is zero

and X and Y are independent

=> $V(C) = 2^2 * V(X) + 4^2 * V(Y)$

substituting values

=> $V(C) = 4 * 8 + 16 * 4$

=> $V(C) = 32 + 64$

=> $V(C) = 96$

The standard deviation is

$\sigma = \sqrt{V(C)}$

substituting values

$\sigma = \sqrt{96}$

$\sigma = 9.798$

6 0

2 years ago

Please answer thanks you (:

dimulka [17.4K]

Answer:

B

Step-by-step explanation:

I believe it is B because it is the only one that doesnt have x values that repeat and give different answers.

Ex. For a, the x value in the first and third coords gives both 1 and 3 as answers.

Every x has to have a unique y value, so

(2,10) (3,12) is ok, but (2,10) (2,12) is not.

Sorry if this doesnt make sense haha

6 0

2 years ago

Discrete or Continuous? Identify the random variables in Exercises 2, 3, 4, 5, 6, 7, 8, 9, 10, and 11 as either discrete or cont

lions [1.4K]

Answer:

Discrete variable

Step-by-step explanation:

We are given the following in the question:

Variable:

Total number of points scored in a football game

Discrete and continuous data:

Discrete data is the data that can be expressed in whole numbers. They cannot take all the values within an interval.
Discrete variables are usually counted and not measured.
Continuous variable can be expressed in fractions and can take any value within an interval.
Continuous variable are usually measured and not counted.

Since, total number of points score in a foot game are expressed in whole numbers and cannot be expressed in decimals, they are discrete variable. They cannot take all the values within an interval and they are usually counted.

Thus,

Total number of points scored in a football game is a discrete variable.

8 0

3 years ago

7. Jackie has one red pencil, one yellow pencil, one blue pencil,

bonufazy [111]

Answer:

Step-by-step explanation:

purple pencil 1/5 = 0.2

black pen 2/3 = 0.67

4 0

3 years ago

Read 2 more answers

14 9/16- 8 1/4 rounded to the nearest whole number

Kipish [7]

Answer:

14 9/16 - 8 1/4 = 14 9/16 - 8 4/16 = 233/16 - 132/16 = 101/16 = 6 5/16 ~~ 6

14 9/16 - 8 1/4 = 6

5 0

3 years ago