Answer:
sorry for blurred image........
Step-by-step explanation:
hope it helps
Hope this is the right one.
Problem 8p^2 - 30p + c
<em>Step One</em>
Take 1/2 of - 30
1/2 * -30 = - 15
<em>Step 2
</em>Square -15
(-15)^2 = 225
c = 225
Problem Nine
a = 1
b = 4
c = -15


x = [-4 +/- sqrt(76)] / 2
x = [-4 +/- 2*sqrt19]/2
x = [-4/2 +/- 2/2 sqrt[19]
x = - 2 +/- sqrt(19)
x1 = - 2 + sqrt(19)
x2 = -2 - sqrt(19)
These two can be broken down more by finding the square root. I will leave them the way they are. It's just a calculator question if you want it to go into decimal form.
Problem Tena = 1
b = 4
c = -32
The discriminate is sqrt(b^2 - 4ac)
D = sqrt(b^2 - 4ac)
D = sqrt(4^2 - 4(1)(-32)
D = sqrt(16 - - 128)
D = sqrt(16 + 128)
D = sqrt(144)
D = +/- 12
Since D can equal + or minus 12 there must be 2 possible (and different) roots. As a matter of fact, this quadratic can be factored.
(x + 8)(x - 4) = y
But that' s not what you were asked for.
The discriminate is > 0 so the roots are going to be real.
<em>
Answer; The discriminate is > 0 so there will be 2 real different roots.</em>
Answer:
Step-by-step explanation:
to find the x-intercept:
Make y=0
0=-8x+4
8x =4
x=4/8
x=1/2
to find y-intercept:
Make x=0
y=-8(0) +4
y=4
Hope this helps!
Mark brainliest if you think I helped! Would really appreciate!
Answer:
x=7 and m<LMN = 120
Step-by-step explanation:
if MO bisects LMN then 13x - 31 must be equal to x + 53
13x - x = 53 + 31
12x = 84
x = 7
and
13x - 31 + x + 53 = m<LMN
14x + 22 = m<LMN
since x is 7
14×7 + 22 = 120
(a) One possibility is 8.45
Rounded to the nearest integer = 8
Rounded to the nearest tenth = 8.5
And rounding this to the nearest integer = 9
(b) The possible numbers are 8.45 to 8.49, inclusively