Translate the given statement into an algebraic inequality or compound inequality

Given that Of 450 college students, 110 are enrolled in math, 205 are enrolled in English, and 50 are enrolled in both. If a student is selected at random

the probability

(a) The student is enrolled in mathematics= $\frac{110}{450} =0.244\\$

(b) The student is enrolled in English.= $\frac{205}{450} =0.456\\$

(c) The student is enrolled in both.= $\frac{50}{450} =0.111\\$

(d) The student is enrolled in mathematics or English.= $\frac{110+205-50}{450} =0.589\\$

(e) The student is enrolled in English but not in mathematics.

= $\frac{205-50}{450} =0.344\\$

(f) The student is not enrolled in English or is enrolled in mathematics.

= $\frac{450-205+110}{450} =0.7889\\$

8 0

3 years ago

A shipping company charges based on calculations of the volume of a rectangular box and the sum of the dimensions of the box. A

Allushta [10]

Answer:

A shipping company charges based on calculations of the volume of a rectangular box and the sum of the dimensions of the box. A square rectangular...

Step-by-step explanation:

7 0

3 years ago

-1.023 + 5.6 (show how you got the answer)

Rom4ik [11]

Answer:

-1.023 + 5.6 = 4.58

Step-by-step explanation:

1. Drop the 3 in -1.023, becoming -1.02

2. Add 0 at the end of 5.6, becoming 5.60

3. Here is the problem you now solve:

-1.02 + 5.60. You can simply type this into your calculator. I hope this helped.

4 0

2 years ago

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