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3 years ago

Someone please help!!

Mathematics

2 answers:

V125BC [204]3 years ago

5 0

The answe is 47 because it’s a 43° point and a 4°

DENIUS [597]3 years ago

4 0

Answer:

Step-by-step explanation:

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Drew's weekly allowance is $8. His friend Jan's weekly allowance is $10. Drew spends $3 a week and Jan spends $4 a week.

Oxana [17]

For drew
5w=55

5w/5=55/5

W=11
11 weeks

For jan

6w= 55

6w/6 = 55/6

W=9.16
9 weeks

Together
6+5 = 11
11w=55
11w/11=55/11
W=5
5 weeks

3 0

4 years ago

Select all of the following equation(s) that are quadratic in form.

charle [14.2K]

Answer:

A, D, E

Step-by-step explanation:

on edg... Good Luck!!

5 0

4 years ago

Which expression is equal to 7/8

myrzilka [38]

7/8 .. *2 = 15/16

7/8 ...* 5 = 35/40

7/8 ...* 10 = 70/80

You can multiply the numerator and denominator by any number ( must be the same number), to result in an equivalent expression

8 0

3 years ago

Please help!!!!!!!!!

exis [7]

Answer u have to add all of it

Step-by-step explanation:

8 0

3 years ago

1)Convert the following binary numbwers into decimal number(only a,b,c,f,i)

kozerog [31]

Answer:

a) 3₁₀

b) 6₁₀

c) 7₁₀

f) 19₁₀

i) 181₁₀

Step-by-step explanation:

Binary to Decimal Conversion (Positional Notation Method)

Multiply each digit by the base (2) raised to the power dependent upon the position of that digit in the binary number.
Sum all the values obtained for each digit.
Express the number as a decimal number by placing subscript 10 after it.

For a binary number with 'n' digits:

The right-most digit is multiplied by 2⁰
The left-most digit is multiplied by $\sf 2^{n-1}$

For example, to convert the binary number 111001₂ into a decimal:

$\begin{array}{ c c c c c c}1 & 1 & 1 & 0 & 0 & 1\\\downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \downarrow \\2^5 & 2^4 & 2^3 & 2^2 & 2^1 & 2^0\\\end{array}$

Multiply each digit by the base (2) raised to the power as indicated above and sum them:

$=(1 \times 2^5)+(1 \times 2^4)+(1 \times 2^3)+(0 \times 2^2)+(0 \times 2^1)+(1 \times 2^0)$

$= 32+16+8+0+0+1$

$= 57$

Finally, express as a decimal number ⇒ 111001₂ = 57₁₀

Question (a)

$\begin{aligned}\implies 11_2 & = (1 \times 2^1)+(1 \times 2^0)\\& = 2+1\\& = 3\end{aligned}$

Therefore, 11₂ = 3₁₀

Question (b)

$\begin{aligned}\implies 110_2 & = (1 \times 2^2)+(1 \times 2^1)+(0 \times 2^0)\\& = 4+2+0\\& = 6\end{aligned}$

Therefore, 110₂ = 6₁₀

Question (c)

$\begin{aligned}\implies 111_2 & = (1 \times 2^2) +(1 \times 2^1)+(1 \times 2^0)\\& =4+2+1\\& = 7\end{aligned}$

Therefore, 111₂ = 7₁₀

Question (f)

$\begin{aligned}\implies 10011_2 & =(1 \times 2^4)+(0 \times 2^3)+ (0 \times 2^2) +(1 \times 2^1)+(1 \times 2^0)\\& =16+0+0+2+1\\& = 19\end{aligned}$

Therefore, 10011₂ = 19₁₀

Question (i)

$\phantom{)))}10110101_2 \\\\=(1 \times 2^7)+(0 \times 2^6)+(1 \times 2^5)+(1 \times 2^4)+(0 \times 2^3)+ (1 \times 2^2) +(0 \times 2^1)+(1 \times 2^0)\\\\=128+0+32+16+0+4+0+1\\\\= 181$

Therefore, 10110101₂ = 181₁₀

8 0

2 years ago

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