You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
Answer:
175 dimes and 75 quarters
Step-by-step explanation:
Make a system of equations, where d is the number of dimes and q is the number of quarters:
d + q = 250
0.1d + 0.25q = 36.25
Solve by elimination by multiplying the top equation by -0.1:
-0.1d - 0.1q = -25
0.1d + 0.25q = 36.25
0.15q = 11.25
q = 75
Then, plug in 75 as q into one of the equations to solve for d:
d + q = 250
d + 75 = 250
d = 175
So, there are 175 dimes and 75 quarters
Answer:
The speed and time are directly proportional in that the higher the speed the lesser the time and vice versa.
The constant is the total distance which is 180 km
Step-by-step explanation:
Step one:
given data
The distance between the two cities is 180km
1.The distance was covered by a car at the rate of 50km/h
The time taken will be
velocity= distance/time
time= distance/velocity
time= 180/50
time= 3.6 hours
2.The distance was covered by a bus 45km/h
The time taken will be
velocity= distance/time
time= distance/velocity
time= 180/45
time= 4 hours
3.The distance was covered by a bicycle at 25km/h
The time taken will be
velocity= distance/time
time= distance/velocity
time= 180/25
time= 7.2 hours
Slope is the best i can think of
Answer:
A.
Step-by-step explanation:
If you use the vertical line test only one point hits the graph.
