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HACTEHA [7]
4 years ago
5

Aspirin and other nonsteroidal anti-inflammatory drugs (NSAID) inhibit inflammation by inhibiting an enzyme in the prostaglandin

pathway. However, inhibiting this enzyme also inhibits other pathways that protect the stomach from damage by stomach acid and that form blood clots. What can you conclude from this? Aspirin and other nonsteroidal anti-inflammatory drugs (NSAID) inhibit inflammation by inhibiting an enzyme in the prostaglandin pathway. However, inhibiting this enzyme also inhibits other pathways that protect the stomach from damage by stomach acid and that form blood clots. What can you conclude from this? The enzyme is found in many different types of cells. Prostaglandins cause blood clotting. Aspirin should not be given to people who people who need to synthesize enzymes. The enzyme inhibition is nonreversible.
Biology
1 answer:
lisov135 [29]4 years ago
8 0

Answer: The enzyme is found in different types of cells.

Explanation:

The result that can be concluded is that this enzyme is found in different types of cells. This is the reason that the medicines like aspirin and other non-steroidal anti inflammatory drugs inhibit the prostaglandin pathway and other pathways too.

These medication acts on the enzymes and it will act in the cells where this enzyme will be present. Hence, the enzyme is acting in different types of cells.

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How does the diameter of each ripple change as time passes
VLD [36.1K]

The diameter of the ripple changes by the following equation = \frac{dA}{dt} = \frac{\pi }{2} D . \frac{d(D)}{dt}<u></u>

<u>Explanation:</u>

When a pebble or a rock is dropped in the water then the ripples or waves are formed which starts moving radially outward. As the time passes, the radius of the circle increases.

Let D be the diameter of the circle.

\frac{dD}{dt} will be the rate of change of diameter of the circle with respect to time.

Let A be the area of the circle.

\frac{dA}{dt} will be the rate of change of area of the circle with respect to time.

Area of the circle = \frac{\pi }{4} D^{2}

So,

\frac{dA}{dt} = \frac{d [\frac{\pi }{4}  D^{2}] }{dt}

\frac{dA}{dt} = \frac{\pi }{4} \frac{d[ D(t)^{2}] }{dt}

<u>Using chain rule,</u>

\frac{dA}{dt} = \frac{\pi }{4}  X  \frac{d[D(t)^{2} ]}{d[D(t)]}   X  \frac{d[D(t)]}{dt}

\frac{dA}{dt} = \frac{\pi }{4}  . 2D(t) . \frac{dD}{dt}

\frac{dA}{dt} = \frac{\pi }{2} X D(t) X \frac{d(D)}{dt}

\frac{dA}{dt} = \frac{\pi }{2} D . \frac{d(D)}{dt}

Thus, the following equation determines the change in area in terms of diameter with respect to time :  \frac{dA}{dt} = \frac{\pi }{2} D . \frac{d(D)}{dt}

7 0
3 years ago
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