Ac=bc and ab= 4 sqr. 2 how long are each of the legs

Mathematics

1 answer:

kykrilka [37]4 years ago

4 0

Answer:

Step-by-step explanation:

ac = bc

ab = 4 sqr. 2 = 4² = 16

ab = 16

ab = ac = 16

the length of each legs is 16

You might be interested in

! Angle Measurement of Polygons ! <br> ~Help my brainless self-~

zloy xaker [14]

Answer:

b) 123

Step-by-step explanation:

6 0

3 years ago

If sin theta = 2/3, which of the following are possible

Ira Lisetskai [31]

Sin ø = opposite/hypotenuse = 2/3, cos ø = adjacent/hypotenuse = ?/3, tan ø = opposite/adjacent = 2/?, sec ø = 1/cos ø

to solve ?, Pythagorean theorem must be applied
hypotenuse^2 = adjacent^2 + opposite^2

Manipulating the equation to find the adjacent value = ?

adjacent = sqrt(hypotenuse^2 - opposite^2) = sqrt(9-4)
adjacent = sqrt(5)

so cos ø = sqrt(5)/3, tan ø = 2/sqrt(5) and sec <span>ø = 3/sqrt(5) since the value is positive the possible equivalent trigonometric function should be positive, the answer should be b </span>

3 0

3 years ago

Read 2 more answers

A dilation has a center (0,0). Find the image of point B (7/5,-5,4) for the scale factor 1/6

AveGali [126]

Answer:

Multiply the coordinate by the scale factor, 1/5 to get (7/25,-5/20). You can simplify this to (7/25, -1/4)

5 0

3 years ago

Please help!!

azamat

Answer:

$sin \theta = \frac{\sqrt {19}}{10}$

Step-by-step explanation:

$( \sin \theta) ^{2} + ( \cos \theta) ^{2} = 1 \\ \\ \therefore \:( \sin \theta) ^{2} + { \bigg( \frac{{9} }{10} \bigg)}^{2}= 1 \\ \\( \sin \theta) ^{2} + \frac{81}{100}= 1 \\ \\ ( \sin \theta) ^{2} = 1 - \frac{81}{100} \\ \\ ( \sin \theta) ^{2} = \frac{100 - 81}{100} \\ \\ ( \sin \theta) ^{2} = \frac{19}{100} \\ \\ \sin \theta = \sqrt{\frac{19}{100} } \\ \\ \sin \theta = \frac{\sqrt {19}}{10}$

7 0

3 years ago

Please help me I stink at math need all

Elena L [17]

7) circle all of them8) write 1/the number it is seperatedby for all three and just divide the shapes evenly9) in thing order: no.no.yes,yes

5 0

3 years ago