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Klio2033 [76]
3 years ago
7

Here is another question that i need help on so here it is 6*5000 and here are the steps:

Mathematics
1 answer:
trasher [3.6K]3 years ago
5 0
Step 3 can be like 2*3*5* ,1*5*6*,3*5*2*,
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t is estimated that Americans buy 2.92×1010 bottles of water per year. At this rate, how many bottles of water are purchased by
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8<span>×10^7 hope this helped</span>
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I need help with this asap please :)
n200080 [17]

Blank 1: If y is -5 when x is 2, that means the equation here is y = -2.5x. So, if x is 8, that makes the equation y = -2.5(8), which gives you -20.

Blank 2: If y is 3 when x is 1, the equation will be y = 3x. If x is 2, that will give you y = 3(2), which is 6.

Blank 3: If y is -7 when x is -21, the equation will be x = 3y. If y is 9, that will give you x = 3(9), which is 27.

Blank 4: If y is 5 when x is 4, the equation will be y = 1.25x. If y is 18, that makes the equation 18 = 1.25x, which is 14.4.


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7 0
3 years ago
Describe a strategy for finding the difference of two temperatures/Answer in complete sentences.
bazaltina [42]

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Use google scooby it's easier than this way.

Step-by-step explanation:

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2 years ago
PLEASE HELP ILL CHOOSE BRAINLIEST!!!!
MAXImum [283]
30÷4=7.5
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3 years ago
Read 2 more answers
Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}

r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

(x-(-2))^2+(y-0)^2=\sqrt{5} ^2

on simplification is

x^{2} +y^{2}+4 x-1=0

5 0
2 years ago
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