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Klio2033 [76]
3 years ago
7

Here is another question that i need help on so here it is 6*5000 and here are the steps:

Mathematics
1 answer:
trasher [3.6K]3 years ago
5 0
Step 3 can be like 2*3*5* ,1*5*6*,3*5*2*,
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Which operation would isolate the variable in this equation?
Blababa [14]

Answer:

D. Divide both sides by - 8

Step-by-step explanation:

-8x = 312

x = 312/(-8)

x = - 39

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3 years ago
−2/3a+1/8−1/6a−3/4 PLS HELP
yarga [219]

Answer:

-5a-15/4

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Step-by-step explanation:

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2 years ago
Is negative 19/3 bigger than negative 6.375
Paul [167]
No its smaller............................
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2 years ago
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Every valid argument with true premises has a true conclusion. Rewrite the above statement in the form V[x] x, if [y] then [z] (
just olya [345]

Answer:

Let y(x)="x is valid and x has true premises" and z(x)="x has a true conclusion".

Step-by-step explanation:

The universe U is the collection of all arguments so that x∈U. The statement uses the universal quantifier ∀ represented by the word "Every". The words "valid", "with true premises" and "has a true conclusions" are properties of an argument x.

We can interptet the statement as: "For all x, (x is valid and x has true premises)→(x has a true conclusion)". Symbolically, (∀x)(y(x)→z(x)). The implication → can be read as "if y(x) then z(x)".

4 0
3 years ago
5#The distribution of scores on a standardized aptitude test is approximately normal with a mean of 480 and a standard deviation
kirza4 [7]

We want to find the value that makes

P(X\ge x)=0.2

To find it we must look at the standard normal table, using the complementary cumulative table we find that

P(Z\ge z)=0.20045\Leftrightarrow z=0.84

Then, using the z-score we can find the minimum score needed, remember that

z=\frac{x-\mu}{\sigma}

Where

σ = standard deviation

μ = mean

And in our example, x = minimum score needed, therefore

\begin{gathered} 0.84=\frac{x-480}{105} \\  \\ x=0.84\cdot105+480 \\  \\ x=568.2 \end{gathered}

Rounding to the nearest integer the minimum score needed is 568, if you get 568 you are at the top 20.1%.

7 0
1 year ago
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