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LenaWriter [7]
3 years ago
13

Please help me thx ​

Mathematics
2 answers:
anyanavicka [17]3 years ago
5 0
The answer is Y=1/26x-2
LiRa [457]3 years ago
4 0

Answer:

y=x/26-2

Step-by-step explanation:

the slope is 1/26 and y intercept is (0,2) or two so you add it into the form.

You might be interested in
-X2 - 2x - 2 over <br> X-2 ? <br> What is the graph of the function f(x) =
alina1380 [7]

Answer:

Hope this helps!

Step-by-step explanation:

6 0
3 years ago
3n - 7 &gt; n + 1 or 4n - 5 &lt; 3n - 3
hodyreva [135]

Answer:

n > 4

Step-by-step explanation:

3n - 7 > <u>n</u> + 1

Move variable to the left side and change its sign

3n <u>- </u><u>n</u> - 7 > 1

...

3n <u>- </u><u>7</u> > n + 1

Move constant to the right side and change its sign

3n - n > 1 <u>+ </u><u>7</u>

...

<u>3</u><u>n - n</u> > 1 + 7

Collect the like terms

<u>2</u><u>n</u> < 1 + 7

...

3n - n > <u>1</u><u> + </u><u>7</u>

Add the numbers

2n < <u>8</u>

Divide both sides of the inequality by 2

Solution:

<u>n </u><u>></u><u> </u><u>4</u><u> </u> Answer:

n < 2

Step-by-step explanation:

4n - 5 < <u>3n</u> - 3

Move variable to the left side and change its sign

4n <u>- 3n</u> - 5 < - 3

...

4n <u>- 5</u> < 3n -3

Move constant to the right side and change its sign

4n - 3n < - 3 <u>+ 5</u>

...

<u>4n - 3n</u> < - 3 + 5

Collect the like terms

<u>n</u> < - 3 + 5

...

4n - 3n < <u>- 3 + 5</u>

Calculate the sum

n < <u>2</u>

...

Solution:

<u>n < 2</u>

8 0
3 years ago
Statement about 23 over six as a mixed number
pickupchik [31]
23/6
23 divided by 6 is 3 remainder 5 so it is 3 5/6

Hope this helps :)

8 0
3 years ago
The expression (x+j)(x-j)(x-k) can be rewritten as x^3-5x^2-4x+t, where j,k, and t are constants. Which of the following is the
kirza4 [7]

The correct option is:  20

<u><em>Explanation</em></u>

The expression (x+j)(x-j)(x-k) can be rewritten as x^3-5x^2-4x+t

That means:   (x+j)(x-j)(x-k)= x^3-5x^2-4x+t

Now simplifying the left side, we will get....

(x+j)(x-j)(x-k)= x^3-5x^2-4x+t\\ \\ (x^2-j^2)(x-k)= x^3-5x^2-4x+t\\ \\ x^3-kx^2-j^2x+j^2k= x^3-5x^2-4x+t

Now <u>comparing the co-effcients of like terms in left and right side</u>, we will get.....

k=5, j^2=4 \\ \\ and\\ \\ t=j^2k\\ \\ So, t= (4)(5) =20

Thus, the value of 't' will be 20.


8 0
3 years ago
Which sequences could be described by the recursive definition LaTeX: a_{n+1}=3\cdot a_n-1a n + 1 = 3 ⋅ a n − 1
JulijaS [17]

Answer:

an=3+an-1

2, 5, 14, 41, 122..

9

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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