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2 years ago

9

JIM TOSSES A BALL IN THE AIR WHEN ON THE COUNT OF 2, 3 , 5 8 13 what numbers will he count when he tosses the ball for the 6th 7

th and 8th time?

1 answer:

DENIUS [597]2 years ago

3 0

Answer:

21, 34, and 55 because it's like that one ratio, I forgot the name tho

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A supermarket needs to display 64 boxes of detergent.

Amiraneli [1.4K]

All the listed combination of row and boxes are correct and can be chosen from.

From the question, we are asked to find the row arrangement of a stack of boxes. Let us take a look at each one of the aforelisted answers

x rows with 16 boxes in each row
8 rows with x boxes in each row
16 rows with x boxes in each row

Since we are told that the total number of boxes to be stacked is 64, then for the first arrangement, we can deduce that the "x" is going to be 4. This is because multiplying 4 by 16 gives 64. For the second row, using the same calculation, we find that "x" is 8. And that of the third gives our "x" to be 4 as well. We can then adjudge that;

4 rows with 16 boxes in each row
8 rows with 8 boxes in each row
16 rows with 8 boxes in each row

Bearing this in mind, we can see that each of the 3 answers fits into the requirements we are asked.

At least 3 rows, and at least 4 boxes in each row.

Hence, all of the options are correct.

To learn more about rows and columns, see here brainly.com/question/13196178

5 0

2 years ago

120% of what number is 48

postnew [5]

Answer:

40

120 percent (calculated percentage %) of what number equals 48? Answer: 40.

8 0

2 years ago

1. The lease common multiple of 3, 4, 6, and 8 is<br> OA. 8.<br> OB. 24.<br> O C.72.<br> OD.96.

almond37 [142]

The answer is ob.24

3 0

2 years ago

Read 2 more answers

Is this correct?<br> (im checking my answers)

zzz [600]

$1L=1,000mL\to1mL=\dfrac{1}{1,000}L=0.001L\\\\0.743mL=0.743(0.001L)=0.000743L\\\\Answer:\ \boxed{0.000743}$

6 0

3 years ago

The table shows the results of an experiment in which subjects taking either a drug or a placebo either reported fatigue or did

Lady bird [3.3K]

Answer:

Therefore, the correct options are;

-P(fatigue) = 0.44

$P(fatigue \left | \right drug)$ = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Step-by-step explanation:

Here we have that for dependent events,

$P(A \, and \, B)= P(A)\times P(B\left | \right A )$

From the options, we have;

$P(fatigue \left | \right drug)$ = 0.533

P(drug) = 0.6

P(drug and fatigue) = 0.32

Therefore

P(drug and fatigue) = P(drug)× $P(fatigue \left | \right drug)$

= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)

Therefore, the correct options are;

-P(fatigue) = 0.44

$P(fatigue \left | \right drug)$ = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.

4 0

2 years ago