Answer:
Each pitcher has the same fraction of the other drink.
Step-by-step explanation:
After 1 cup of tea is added to x cups of lemonade, the mix has the ratio 1:x of tea to lemonade. So, the fraction of mix that is tea is 1/(x+1).
The 1 cup of mix contains 1/(x+1) cups of tea and so x/(x+1) cups of lemonade. When that amount of lemonade is added to the tea, it brings the proportion of lemonade in the tea to (x/(x+1))/x = 1/(x+1), the same proportion as that of tea in the lemonade.
_____
You can consider the degenerate case of one cup of drink in each pitcher. Then when the 1 cup of tea is removed from its pitcher and added to the lemonade, you have a 50-50 mix of tea and lemonade. Removing 1 cup of that mix and putting it back in the tea pitcher makes there be a 50-50 mix in both pitchers.
Increasing the quantity in each pitcher does nothing to change the fact that the mixes end up in the same ratio:
tea:lemonade in Pitcher 1 = lemonade:tea in Pitcher 2
Answer:
To solve for n you need to get it by itself
First you want to distribute your 2 through the (3n+14)
-2n+6n+28=-20 (2*3n+2*14= 6n+28)
Now you want to combine any like terms if possible
4n+28=-20 (-2n+6n=4n, both like terms)
Then you want to subtract -28 from both sides
4n=-48 (28-28=0, -20-28=-48)
Lastly you want to divide both sides by 4
n=-12 (4n/4=n, -48/4= -12)
Answer:
(3×3)+2=11
$11
Step-by-step explanation:
BD = AC/2
4x+2 = (5x+13)/2
2(4x+2) = 5x+13
8x + 4 = 5x+13
8x - 5x = 13 -4
3x = 9
x = 3
Answer:
12:07pm
Step-by-step explanation:
first common multiple of 60 and 70 is 420
420 s = 7 mins
