D 2. Choose the correct answer to 2,412 : 25. 96 R12 96 97 95 R37

Hello, I need help I have watched about 10+ hours of YT videos on this and still don't understand this and my teacher wont respo

suter [353]

Answer:

On the first one, they took half of the original number then added it to the original to get the sides of the bigger shape.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Priya has completed 9 exam questions this is 60% of the questions on the exam. Write an equation representing this situation. Ex

krek1111 [17]

Answer:

9=0.6q where q is the number of questions on the exam.

Step-by-step explanation:

3 0

3 years ago

Write the following as an inequality 6 is greater than or equal to x and -2 is less than or equal to x

kipiarov [429]

Answer:

-2 ≤ x ≤ 6

Step-by-step explanation:

The first is ...

6 ≥ x

and it can also be written as ...

x ≤ 6

The second is

-2 ≤ x

The two inequalities can be combined into one compound inequality:

-2 ≤ x ≤ 6

_____

Comment on this answer

I prefer the answer in this form because it puts the parts of the expression in the same order that they appear on a number line. It can also be written as ...

6 ≥ x ≥ -2

7 0

4 years ago

Can someone please solve this, tell me which one goes where in order.

sasho [114]

Total discount for 10 group tickets = 10 · 0.05t

Amount of discount per ticket = 0.05t

Number of tickets = 10

Cost of buying 10 single tickets = 10t

Solution:

Cost for single ticket = t dollars

Discount percent per ticket = 5%

Number of tickets bought = 10

Total discount for 10 group tickets = Number of tickets × Discount amount

= 10 × 0.05t

Total discount for 10 group tickets = 10 · 0.05t

Amount of discount per ticket = 5%t

= $\frac{5}{100}$ t

= 0.05t

Amount of discount per ticket = 0.05t

Number of tickets = 10

Cost of buying 10 single tickets = 10t

4 0

4 years ago

When a bactericide is added to a nutrient broth in which bacteria are growing, the bacteria population continues to grow for a

baherus [9]

Answer:

a) 1296 bacteria per hour

b) 0 bacteria per hour

c) -1296 bacteria per hour

Step-by-step explanation:

We are given the following information in the question:

The size of the population at time t is given by:

$b(t) = 9^6 + 6^4t-6^3t^2$

We differentiate the given function.

Thus, the growth rate is given by:

$\displaystyle\frac{db(t)}{dt} = \frac{d}{dt}(9^6 + 6^4t-6^3t^2)\\\\= 6^4-2(6^3)t$

a) Growth rates at t = 0 hours

$\displaystyle\frac{db(t)}{dt} \bigg|_{t=0}= 6^4-2(6^3)(0) = 1296\text{ bacteria per hour}$

b) Growth rates at t = 3 hours

$\displaystyle\frac{db(t)}{dt} \bigg|_{t=3}= 6^4-2(6^3)(3) = 0\text{ bacteria per hour}$

c) Growth rates at t = 6 hours

$\displaystyle\frac{db(t)}{dt} \bigg|_{t=6}= 6^4-2(6^3)(6) = -1296\text{ bacteria per hour}$

3 0

4 years ago