Find all zeros and write the answers in factored form<br> (x-5)(3x^2-8x+6) =0

What is the equation of the line that passes through the point (-5,-4) and has a slope of -3/5

vagabundo [1.1K]

Answer:

y= -3/5x - 7 (assuming slope-intercept form)

Step-by-step explanation:

First, we see the slope. The basic template for a slope-intercept question is

y=mx + b

So, we put in -3/5 as "m" in this case, as it is the slope to get y= -3/5x +b

To find b, we can just try out the point that the equation gave us.

-3/5 * -5 = 3

Then, to get to -4 from 3, we need to subtract 7.

Then, we get our whole slope-intercept equation. y=-3/5x - 7

8 0

3 years ago

Read 2 more answers

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

From the first equation:

$d_1 = 40t_1$

$t_1 = \frac{d_1}{40}$

Replacing in the second equation:

$60 = \frac{d_1 - 20}{t_1 - 2}$

$d_1 - 20 = 60t_1 - 120$

$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

$-\frac{d_1}{2} = -100$

$\frac{d_1}{2} = 100$

$d_1 = 200$

Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0

3 years ago

an initial population of 700 trout increases at an annual rate of 22%. Which exponential function models the trout population?

REY [17]

Answer:

$y=700(1.22)^{x}$

Step-by-step explanation:

Let

y-----> the trout population

x----> the time in years

we know that

$22\%=22/100=0.22$

$y=700(1+0.22)^{x}$

$y=700(1.22)^{x}$ ----->exponential function that models the trout population

7 0

3 years ago

Find the center and radius when x^2+y^2+4x-4y=17

coldgirl [10]

Answer:

the center is (-2,2) and the radius is 5

3 0

3 years ago

Read 2 more answers

Determine whether each of the following pairs of angles have equal measures. Drag and drop each pair

never [62]

Answer:

MJK & PJR = Unequal

LJP & NJR = Equal

KJR & MJP = Equal ? (not too sure with this one)

MJP & PJR = Unequal

KJL & LJM = Unequal

8 0

4 years ago

Find all zeros and write the answers in factored form (x-5)(3x^2-8x+6) =0