I think the answer is 42 miles
Hello from MrBillDoesMath!
Answer:
1/3
Discussion:
The problem looks complicated until you realize the term n^-4 appears in both the numerator and denominator. Hence their quotient is 1. That is,
n ^(-4) / ( 3 * n^(-4)) =
(n ^(-4) / n^(-4) ) * (1/3) =
1 * (1/3) =
1/3
Thank you,
MrB
1. x^2 + y^2 - 4x + 12y - 20 = 0 ---- (x-2)^2 + (y+6)^2 = 60
3. 3x^2+ 3y^2 + 12x +18y - 15 = 0 --- (x+2)^2 + (y+3)^2 = 18
5. 2x^2 + 2y^2 - 24x - 16y - 8 = 0 --- (x-6)^2 + (y-4)^2 = 56
I don't know the other two, hope I helped though.
Answer:
Option D. 9
Step-by-step explanation:
There are two ways to obtain the answer to the question.
Method 1:
Let 2x + 1 = 0
Making x the subject, we have
2x + 1 = 0
Collect like terms
2x = –1
Divide both side by 2
x = –1/2
Now, put the value of x into the expression 4x³ – 6x² – 8x + 7, we have:
4x³ – 6x² – 8x + 7
x = –1/2
4(–1/2)³ – 6(–1/2)² – 8(–1/2) + 7
4(–1/8) – 6(1/4) – 8(–1/2) + 7
–1/2 – 3/2 + 4 +7
– 4/2 + 4 + 7
– 2 + 4 + 7
= 9
Method 2:
Divide 4x³ – 6x² – 8x + 7 by 2x + 1
Please see attached photo for explanation.
Number 7: 11/12-9/10 = 110/120-108/120=2/120= 1/60
number 8: 5/18-1/3=15/54-5/54=10/54 =5/27